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7. Aluminum metal weighing 2.82 g is exposed to 2.56 g oxygen gas to produce aluminum oxide. (Molar Masses: Al-26.98 g/mol, O₂ -32.00 g/mol, Al2O3 -101.96 g/mol) What is the limiting reactant and what is the maximum theoretical moles of the product? Al, 0.0523 moles from Al Al, 0.105 moles from Al 406 O2, 0.0533 moles from O₂ O2, 0.0800 moles from O₂

7. Aluminum metal weighing 2.82 g is exposed to 2.56 g oxygen gas to produce aluminum oxide. (Molar Masses: Al-26.98 g/mol, O₂ -32.00 g/mol, Al2O3 -101.96 g/mol) What is the limiting reactant and what is the maximum theoretical moles of the product? Al, 0.0523 moles from Al Al, 0.105 moles from Al 406 O2, 0.0533 moles from O₂ O2, 0.0800 moles from O₂

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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7. Aluminum metal weighing 2.82 g is exposed to 2.56 g oxygen gas to produce aluminum oxide. (Molar Masses: Al-26.98 g/mol, O₂ -32.00 g/mol, Al2O3 -101.96 g/mol) What is the limiting reactant and what is the maximum theoretical moles of the product? Al, 0.0523 moles from Al Al, 0.105 moles from Al O2, 0.0533 moles from O₂ O2, 0.0800 moles from O2
Transcribed Image Text:7. Aluminum metal weighing 2.82 g is exposed to 2.56 g oxygen gas to produce aluminum oxide. (Molar Masses: Al-26.98 g/mol, O₂ -32.00 g/mol, Al2O3 -101.96 g/mol) What is the limiting reactant and what is the maximum theoretical moles of the product? Al, 0.0523 moles from Al Al, 0.105 moles from Al O2, 0.0533 moles from O₂ O2, 0.0800 moles from O2
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