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7. - A wire is bent into a loop in the shape of two circular arcs of radii a 20 cm and b = 25 cm as shown below. Assume a uniform magnetic field is produced by an unseen electromagnet. The field is drawn as the array of dots. The electromagnet is programmed to increase the field strength at a rate of 12.0 mT per second. a. Draw arrow heads on the wire to indicate the direction of the induced current. b. Calculate the magnitude of the EMF induced in the wire.

7. - A wire is bent into a loop in the shape of two circular arcs of radii a 20 cm and b = 25 cm as shown below. Assume a uniform magnetic field is produced by an unseen electromagnet. The field is drawn as the array of dots. The electromagnet is programmed to increase the field strength at a rate of 12.0 mT per second. a. Draw arrow heads on the wire to indicate the direction of the induced current. b. Calculate the magnitude of the EMF induced in the wire.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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7. d A wire is bent into a loop in the shape of two circular arcs of radii a - 20 cm and b = 25 cm as shown below. Assume a uniform magnetic field is produced by an unseen electromagnet. The field is drawn as the array of dots. The electromagnet is programmed to increase the field strength at a rate of 12.0 mT per second. W Again, refer to Fig. 1. Suppose the power supply connected to the solenoid increases the magnitude of the magnetic field as a function of time. a. Draw arrow heads on the wire to indicate the direction of the induced current. Determine the direction of the induced current in the wire loop. Explain your reasoning in a detailed, step-by-step manner. b. Calculate the magnitude of the EMF induced in the wire. Suppose the induced current in the circular loop is measured to be I(t) = kt in Amps. The resistance of the wire loop is z Ohms. Determine an expression for the magnitude of the induced EMF in the wire loop as a function of time. 70 Insert the answer to the previous into Faraday's Law and simplify the equation. The area integration for the flux will just give the area of the circular loop. Let the radius of the circle be a. Integrate both sides of Faraday's law to obtain an expression for the magnitude of the primary magnetic field as a function of time. The primary magnetic field is the solenoid's magnetic field. It is what causes the induction, in the first place. $E -di 20 $(5×B)-dl P₁ = ff B.dÃ
Transcribed Image Text:7. d A wire is bent into a loop in the shape of two circular arcs of radii a - 20 cm and b = 25 cm as shown below. Assume a uniform magnetic field is produced by an unseen electromagnet. The field is drawn as the array of dots. The electromagnet is programmed to increase the field strength at a rate of 12.0 mT per second. W Again, refer to Fig. 1. Suppose the power supply connected to the solenoid increases the magnitude of the magnetic field as a function of time. a. Draw arrow heads on the wire to indicate the direction of the induced current. Determine the direction of the induced current in the wire loop. Explain your reasoning in a detailed, step-by-step manner. b. Calculate the magnitude of the EMF induced in the wire. Suppose the induced current in the circular loop is measured to be I(t) = kt in Amps. The resistance of the wire loop is z Ohms. Determine an expression for the magnitude of the induced EMF in the wire loop as a function of time. 70 Insert the answer to the previous into Faraday's Law and simplify the equation. The area integration for the flux will just give the area of the circular loop. Let the radius of the circle be a. Integrate both sides of Faraday's law to obtain an expression for the magnitude of the primary magnetic field as a function of time. The primary magnetic field is the solenoid's magnetic field. It is what causes the induction, in the first place. $E -di 20 $(5×B)-dl P₁ = ff B.dÃ
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