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7. A composite wall consists of three materials, as shown in Figure 2. The inside wall temperature is 200°C and the outside air temperature is 50°C with a convection coefficient of 10 W/m²-K. Determine the temperature along the composite wall. Where A is the area of cross- section (can be taken to be equal to 1) and k is the conductivity. Problem is governed by the equation d²T -kA dx2 = 0, 0

7. A composite wall consists of three materials, as shown in Figure 2. The inside wall temperature is 200°C and the outside air temperature is 50°C with a convection coefficient of 10 W/m²-K. Determine the temperature along the composite wall. Where A is the area of cross- section (can be taken to be equal to 1) and k is the conductivity. Problem is governed by the equation d²T -kA dx2 = 0, 0

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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7. A composite wall consists of three materials, as shown in Figure 2. The inside wall temperature is 200°C and the outside air temperature is 50°C with a convection coefficient of 10 W/m²-K. Determine the temperature along the composite wall. Where A is the area of cross- section (can be taken to be equal to 1) and k is the conductivity. Problem is governed by the equation d²T -kA- = 0, 0<x<L dx2 Boundary conditions d²T T(0) = To, kA dx2 +BA(T – T)| = 0 Where A is the area of cross-section (cab be taken to be equal 1) and k is the conductivity. Material 2. k k = 70 WAm K) Material 1, k „Material 3, kz Ag - 40 WAm K) ky = 20 W(m-K) T 50°C Surface arca L =2 cm T,- 200°C A(1) L 2.5 em L =4 cm B= 10 WAm- K) 2 3 4 Figure 2
Transcribed Image Text:7. A composite wall consists of three materials, as shown in Figure 2. The inside wall temperature is 200°C and the outside air temperature is 50°C with a convection coefficient of 10 W/m²-K. Determine the temperature along the composite wall. Where A is the area of cross- section (can be taken to be equal to 1) and k is the conductivity. Problem is governed by the equation d²T -kA- = 0, 0<x<L dx2 Boundary conditions d²T T(0) = To, kA dx2 +BA(T – T)| = 0 Where A is the area of cross-section (cab be taken to be equal 1) and k is the conductivity. Material 2. k k = 70 WAm K) Material 1, k „Material 3, kz Ag - 40 WAm K) ky = 20 W(m-K) T 50°C Surface arca L =2 cm T,- 200°C A(1) L 2.5 em L =4 cm B= 10 WAm- K) 2 3 4 Figure 2
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