7 What valence orbitals (hybridized and/or nonhybridized) are available on an sphybridized carbon atom?

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### Understanding Valence Orbitals in an sp Hybridized Carbon Atom

**Question 7:**  
What valence orbitals (hybridized and/or nonhybridized) are available on an sp-hybridized carbon atom?

**Explanation:**

In an sp-hybridized carbon atom, hybridization involves the mixing of one s orbital and one p orbital from the valence shell to form two equivalent sp orbitals. This leaves two unhybridized p orbitals. The hybridization process can be summarized as follows:

1. **Hybridized Orbitals:**
   - **2 sp Orbitals:** These orbitals are linear and are oriented 180 degrees apart, suitable for forming strong sigma bonds.
   
2. **Nonhybridized Orbitals:**
   - **2 p Orbitals:** These orbitals remain unhybridized and are available for forming pi bonds.

This configuration is typical in molecules with triple bonds, such as acetylene, where the two sp orbitals are involved in sigma bonding, and the two p orbitals form pi bonds. Understanding these concepts is crucial for predicting the geometry and bonding properties of molecules containing carbon atoms.
Transcribed Image Text:### Understanding Valence Orbitals in an sp Hybridized Carbon Atom **Question 7:** What valence orbitals (hybridized and/or nonhybridized) are available on an sp-hybridized carbon atom? **Explanation:** In an sp-hybridized carbon atom, hybridization involves the mixing of one s orbital and one p orbital from the valence shell to form two equivalent sp orbitals. This leaves two unhybridized p orbitals. The hybridization process can be summarized as follows: 1. **Hybridized Orbitals:** - **2 sp Orbitals:** These orbitals are linear and are oriented 180 degrees apart, suitable for forming strong sigma bonds. 2. **Nonhybridized Orbitals:** - **2 p Orbitals:** These orbitals remain unhybridized and are available for forming pi bonds. This configuration is typical in molecules with triple bonds, such as acetylene, where the two sp orbitals are involved in sigma bonding, and the two p orbitals form pi bonds. Understanding these concepts is crucial for predicting the geometry and bonding properties of molecules containing carbon atoms.
Expert Solution
Step 1

step 1) Introduction :

Carbon has to form 2 covalent bonds which results in CH2, it is having 2 unpaired electrons in its electronic configuration .This is according to the valence bond theory.

Carbon has 4 unpaired electrons so to form 4 bonds the configuration of carbon exists as CH4 .

CH4 has 2s and 2p orbitals which fused to form four equal sp3 hybrid orbitals.

 

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