Explain the determine yellow 226Difference Equationsthen()kkak(7.92)eAgain, substitution of equation (7.92) into equation (7.80) gives- (k+1)(*)k +1Ck+1Ck.(7.93)= ekNote that for k → 0, this equation becomesCk+1 ~ Ck,(7.94)which implies that c ~ constant. Hence, in order to determine the dominantCk, higher-order terms must be included in the k dependent factorbehavior ofon the right side of equation (7.93).To proceed, define A(k) as follows:-(k+1)A(k) = e1+(7.95)Therefore, for k → 0, we havelog A = log(e) – (k +1) log ( 1+1= 1- (k + 1)k111(7.96)2k23k34k41112k6k212k3and111A(k)exp2k6k212k3(7.97)1112k6k212k3r=If only terms to order k-3 are retained, then1+2k11111A(k)1++..6k212k324k26k38k31712k3+...24k216k3(7.98)Hence, Ck obeys the difference equation:).1712k(7.99)Ck+1 =+...Ck•24k216k3APPLICATIONS227 l stc ksa2:37 PMC @ 1 65% 4equationak+1 == kak.(7.80)This follows directly from the results of Section 2.4. To determine the dom-inant or leading behavior of the solution to equation (7.80), we rewrite it inthe formCancelActual Size (410 KB)Choose

Name: Explain the determine yellow 226Difference Equationsthen()kkak(7.92)eA
Uploaded: 2024-03-20T06:47:08.000Z
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Description: Explain the determine yellow 226Difference Equationsthen()kkak(7.92)eAgain, substitution of equation (7.92) into equation (7.80) gives- (k+1)(*)k +1Ck+1Ck.(7.93)= ekNote that for k → 0, this equation becomesCk+1 ~ Ck,(7.94)which implies that c ~ cons