Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![## Problem 7: Applying the Quadratic Formula
**Instruction:**
Input the correct values into the quadratic formula below:
Given Quadratic Equation:
\[ 4x^2 + 3x - 2 = 0 \]
**Quadratic Formula:**
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
**Interactive Template:**
\[ x = \frac{- \boxed{\phantom{a}} \pm \sqrt{\boxed{\phantom{a}}^2 - 4 \cdot \boxed{\phantom{a}} \cdot \boxed{\phantom{a}}}}{2 \cdot \boxed{\phantom{a}}} \]
**Step-by-Step Explanation:**
To solve the quadratic equation using the quadratic formula, follow these steps:
1. **Identify the coefficients** from the given quadratic equation \(ax^2 + bx + c = 0\).
- **a:** The coefficient of \(x^2\).
- **b:** The coefficient of \(x\).
- **c:** The constant term.
2. **Input the values** of a, b, and c into the template.
3. **Simplify** the expression under the square root (the discriminant).
4. **Calculate** the final values by simplifying the expression.
**Example with the Given Equation:**
For the equation \(4x^2 + 3x - 2 = 0\):
- \(a = 4\)
- \(b = 3\)
- \(c = -2\)
**Substitute these values into the formula:**
\[ x = \frac{- \boxed{3} \pm \sqrt{\boxed{3}^2 - 4 \cdot \boxed{4} \cdot \boxed{-2}}}{2 \cdot \boxed{4}} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78a256bd-ea52-4682-957b-1448c364f8ac%2Ff3e612e7-4f01-46b7-92db-1570f014363b%2Fzwqmxlf_processed.png&w=3840&q=75)
Transcribed Image Text:## Problem 7: Applying the Quadratic Formula
**Instruction:**
Input the correct values into the quadratic formula below:
Given Quadratic Equation:
\[ 4x^2 + 3x - 2 = 0 \]
**Quadratic Formula:**
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
**Interactive Template:**
\[ x = \frac{- \boxed{\phantom{a}} \pm \sqrt{\boxed{\phantom{a}}^2 - 4 \cdot \boxed{\phantom{a}} \cdot \boxed{\phantom{a}}}}{2 \cdot \boxed{\phantom{a}}} \]
**Step-by-Step Explanation:**
To solve the quadratic equation using the quadratic formula, follow these steps:
1. **Identify the coefficients** from the given quadratic equation \(ax^2 + bx + c = 0\).
- **a:** The coefficient of \(x^2\).
- **b:** The coefficient of \(x\).
- **c:** The constant term.
2. **Input the values** of a, b, and c into the template.
3. **Simplify** the expression under the square root (the discriminant).
4. **Calculate** the final values by simplifying the expression.
**Example with the Given Equation:**
For the equation \(4x^2 + 3x - 2 = 0\):
- \(a = 4\)
- \(b = 3\)
- \(c = -2\)
**Substitute these values into the formula:**
\[ x = \frac{- \boxed{3} \pm \sqrt{\boxed{3}^2 - 4 \cdot \boxed{4} \cdot \boxed{-2}}}{2 \cdot \boxed{4}} \]
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