7 > void output(const int a[], const int &SIZE) {=} 19 20 > bool isSafePosition(const int a[], const int &SIZE, int row, int col) {-} 41 42 > bool solve(int a[], const int &SIZE, int row) {=} 75 76 v int main() { cout <« endl; 77 78 79 // create an array and populate it with -1 to represent an empty board 80 const int SIZE = 8; 81 int a[SIZE]; 32 for(int i=0; i<$IZE; i++) { a[i] = -1; } // solve the recursive problem solve(a, SIZE, 0); 64 85 86 87 cout <« endl; 88 return 0; 89 Last login: Thu Mar 26 15:19:40 on ttyse00 srtev - X /var/folders/nr/094m7xqx66j4hc1v96cjbhwce00@gn/T/separate_compilation_p2 ; exit; check: e e check: 1 0 check: 1 1 check: 1 2 check: 2 0 check: 2 1 check: 2 2 check: 2 3 BACKTRACK TO ROW 1 check: 1 3 check: 2 e check: 2 1 check: 3 0 check: 3 1 check: 3 2 check: 3 3 BACKTRACK TO ROW 2 check: 2 2 check: 2 3 BACKTRACK TO ROW 1

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I'm stuck on this question and I don't know how I should be approaching this. What should I do?
 
Question:
------------------
Solving the N-Queens Problem
 
Main Function
 
Create a one-dimensional array of size n and seed it with -1 values. This represents an empty n x n chess board. Develop the problem with n=4, test the solution up to n=24. Note that the array index represents the row, and array value the column.
 
Print Function
 
Print the array where all -1 values are empty spots on the board and all values not equal to -1 represent the position of a queen.
 
isSafePosition
 
Test if a specific row/col position is safe for a queen relative to all previous rows (row-1). If placing a queen into this specific row/col position would be dangerous return false, else return true.
 
Solve
 
Use backtracking to provide a solution for the current board size. This is a recursive function which repeatedly tests different queen layouts until it ultimately finds a working solution.
 
Your implementation should be based off of the following design:
 
My code so far:
------------------
#include <iostream>
using namespace std;

void print(const int a[], const int &SIZE) {
for(int i=0; i<SIZE; i++){
for(int j = 0; j<SIZE;j++){
if (j == a[i]){
cout<<"Q";
}
else{
cout<<".";
}
}
cout<<endl;
}
}

bool isSafePosition(const int a[], const int &SIZE, int row, int col){
for(int i=0; i<SIZE; i++){
for(int j = i+1; j<SIZE; j++){
if(a[i] == a[j])
returnfalse;
if (row - 1 == col)
returnfalse;
}
}
returntrue;
}

bool solve(int a[], const int &SIZE, int row){
if(row == SIZE){
returntrue;
}
else if(row < SIZE){
for(int row = 0; row<4; row++){
for(int col = 0; col<4; col++)
cout<<"Check: "<<row<<" "<<col<<endl;
cout<<endl;
print()
 
}
}
}

int main(){
cout<<endl;

const int SIZE = 4;
int a[SIZE];
for(int i=0; i<SIZE; i++){a[i] = -1;}

solve(a, SIZE, 0);

cout<<endl;
return0;
}
7 > void output(const int a[], const int &SIZE) {=}
19
20 > bool isSafePosition(const int a[], const int &SIZE, int row, int col) {-}
41
42 > bool solve(int a[], const int &SIZE, int row) {=}
75
76 v int main() {
cout <« endl;
77
78
79
// create an array and populate it with -1 to represent an empty board
80
const int SIZE = 8;
81
int a[SIZE];
32
for(int i=0; i<$IZE; i++) { a[i] = -1; }
// solve the recursive problem
solve(a, SIZE, 0);
64
85
86
87
cout <« endl;
88
return 0;
89
Transcribed Image Text:7 > void output(const int a[], const int &SIZE) {=} 19 20 > bool isSafePosition(const int a[], const int &SIZE, int row, int col) {-} 41 42 > bool solve(int a[], const int &SIZE, int row) {=} 75 76 v int main() { cout <« endl; 77 78 79 // create an array and populate it with -1 to represent an empty board 80 const int SIZE = 8; 81 int a[SIZE]; 32 for(int i=0; i<$IZE; i++) { a[i] = -1; } // solve the recursive problem solve(a, SIZE, 0); 64 85 86 87 cout <« endl; 88 return 0; 89
Last login: Thu Mar 26 15:19:40 on ttyse00
srtev - X /var/folders/nr/094m7xqx66j4hc1v96cjbhwce00@gn/T/separate_compilation_p2 ; exit;
check: e e
check: 1 0
check: 1 1
check: 1 2
check: 2 0
check: 2 1
check: 2 2
check: 2 3
BACKTRACK TO ROW 1
check: 1 3
check: 2 e
check: 2 1
check: 3 0
check: 3 1
check: 3 2
check: 3 3
BACKTRACK TO ROW 2
check: 2 2
check: 2 3
BACKTRACK TO ROW 1
Transcribed Image Text:Last login: Thu Mar 26 15:19:40 on ttyse00 srtev - X /var/folders/nr/094m7xqx66j4hc1v96cjbhwce00@gn/T/separate_compilation_p2 ; exit; check: e e check: 1 0 check: 1 1 check: 1 2 check: 2 0 check: 2 1 check: 2 2 check: 2 3 BACKTRACK TO ROW 1 check: 1 3 check: 2 e check: 2 1 check: 3 0 check: 3 1 check: 3 2 check: 3 3 BACKTRACK TO ROW 2 check: 2 2 check: 2 3 BACKTRACK TO ROW 1
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