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7) A1,000[kg] rock is moved from the north end of a parking lot to the south end. The parking lot is horizontal and the length of the parking lot is 10[m]. How much work needs to be done to the rock? O[J] 10[J] 100[J] 1,000[J] E) 10,000[J] More information needs to be given D)

7) A1,000[kg] rock is moved from the north end of a parking lot to the south end. The parking lot is horizontal and the length of the parking lot is 10[m]. How much work needs to be done to the rock? O[J] 10[J] 100[J] 1,000[J] E) 10,000[J] More information needs to be given D)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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7) A 1,000[kg] rock is moved from the north end of a parking lot to the south end. The parking lot is horizontal and the length of the parking lot is 10[m]. How much work needs to be done to the rock? XA) B) C) O[J] 10[J] 100[J] D) 1,000[J] 10,000[J] F) More information needs to be given
Transcribed Image Text:7) A 1,000[kg] rock is moved from the north end of a parking lot to the south end. The parking lot is horizontal and the length of the parking lot is 10[m]. How much work needs to be done to the rock? XA) B) C) O[J] 10[J] 100[J] D) 1,000[J] 10,000[J] F) More information needs to be given
Expert Solution
Step 1

Since, work done(W) is defined as the product of Force(F) and displacement(d).Mathematically:-

 

W=F.d=(ma).d

Where m=mass and a=acceleration.

 

Since in above problem, only mass(m) and displacement(d) is given, acceleration(a) is not given.

Hence, in order to get the value of work done(W), acceleration(a) value is needed.

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