7 7 = 3, f(x)dx = 8, and g(x)dx = 5. Evaluate the following integrals. Sowar=s. 2 2 2 Sawak = -5 7 (Simplify your answer.) 7 3g(x)dx = 2 (Simplify your answer.)

Q: (21 + V3)/3 11 dx Evaluate 50 + x - 14x

A: Explanation of the answer is as follows

Q: L dx x-1 -1 -x²+1

A:

Q: Find - 6x+1 x² +1 -dx.

A:

Q: dx 4. 8 + 2r2

A: The solution of the problem is given in the next step.

Q: -2 Evaluate (5х — 2) dx -6

A:

Q: f. S r4 dx J2 xV2-2x2 2.

A:

Q: dx Vx + a + Vx + b

A: Given: The integral is ∫xx+a+x+bdx

Q: 2 dx 8x + 9

A: To find the value of given integration  We use some basic results of integration and substitution

Q: 3x? dx 2 + 4x

A:

Q: 5 x´ - 9 -9- +2)x dx X 5.

A:

Q: dx 4x2- 4x+5

A:

Q: 7x2 + 15 dx. x2 + x Compute f

A:

Q: Show that (xcos(2x)dx=. A-2 8

A: LetI=∫0π4xcos2xdxPut 2x=udifferentiate on both side2dx=dudx=du2As x→0 then u→0As x→π4 then…

Q: 5. (2x + 3V )dx 2х + 3уx

A:

Q: 7) (3x* – 5)° . 36.x dx

A: 7) the given integral is (3x4-5)536x3 3) the given integral is (x3-2)-43x2.

Q: 2 X 2 X 0+ - 4 +4 dx =

A: C+C

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: dx 5. x/2 +x/3

A:

Q: -dx x +1 2 5.

A:

Q: 1 3. Evaluate dx, using substitution method. 2

A: The given integral is: ∫1xx+12dx I=∫1xx+12dx    -1

Q: Evaluate x(x2 + 1)3 dx.

A: Given ∫x(x2+1)3dx

Q: 2 dx Evaluate J xvx4 + 25

A:

Q: 3 dx 4+x2 00 Find

A: Let I=∫2∞34+x2dx. Simplify the integration I by using the constant multiple rule.…

Q: 00 x3 dx (x²+1)² it

A:

Q: I. Evaluate x² +6 12 x³ + 3x dx.

A: Given, Evaluate ∫x2+6x3+3xdx

Q: 2x² − x +4 x³ + 4x Evaluate [ [20 dx.

A: Evaluate