7 2, R4 = 4 S2, I¡ = 2 A, I2 = 1 A. 2 Use nodal analysis to find node voltages V1, V½, and V3 in Figure P3.32. Let R¡ = 10 2, R2 = 62, %3| R3 %3D

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Author:Robert L. Boylestad
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Construct the load line of the circuit from Problem 3.32 assuming that R4 is the load device.

**Educational Resource: Nodal Analysis Example**

**Objective:**
Use nodal analysis to find the node voltages \( V_1, V_2, \) and \( V_3 \) in Figure P3.32.

**Given Values:**
- \( R_1 = 10 \, \Omega \)
- \( R_2 = 6 \, \Omega \)
- \( R_3 = 7 \, \Omega \)
- \( R_4 = 4 \, \Omega \)
- \( I_1 = 2 \, \text{A} \)
- \( I_2 = 1 \, \text{A} \)

**Diagram Explanation:**

- The circuit diagram consists of three nodes labeled \( V_1, V_2, \) and \( V_3 \).
- Node \( V_1 \) is connected to a current source \( I_1 \) (2A) and resistor \( R_1 \) (10Ω).
- Node \( V_2 \) is the central node, connected to resistors \( R_1 \), \( R_2 \) (6Ω), and a current source \( I_2 \) (1A).
- Node \( V_3 \) is connected to resistor \( R_2 \) and resistor \( R_4 \) (4Ω).
- Node \( V_2 \) is also connected to ground via resistor \( R_3 \) (7Ω).

**Circuit Configuration:**

- The current source \( I_1 \) is directly feeding into node \( V_2 \).
- Node \( V_2 \) is the junction point for all resistors and current sources:
  - Connected to ground through \( R_3 \)
  - Connected to node \( V_1 \) through \( R_1 \)
  - Connected to node \( V_3 \) through \( R_2 \) and \( R_4 \)
- The circuit forms a closed loop, ensuring continuity for current flow.

This example serves as a practice case for students to apply the nodal analysis technique that helps in finding the potential difference across different points in an electrical circuit.
Transcribed Image Text:**Educational Resource: Nodal Analysis Example** **Objective:** Use nodal analysis to find the node voltages \( V_1, V_2, \) and \( V_3 \) in Figure P3.32. **Given Values:** - \( R_1 = 10 \, \Omega \) - \( R_2 = 6 \, \Omega \) - \( R_3 = 7 \, \Omega \) - \( R_4 = 4 \, \Omega \) - \( I_1 = 2 \, \text{A} \) - \( I_2 = 1 \, \text{A} \) **Diagram Explanation:** - The circuit diagram consists of three nodes labeled \( V_1, V_2, \) and \( V_3 \). - Node \( V_1 \) is connected to a current source \( I_1 \) (2A) and resistor \( R_1 \) (10Ω). - Node \( V_2 \) is the central node, connected to resistors \( R_1 \), \( R_2 \) (6Ω), and a current source \( I_2 \) (1A). - Node \( V_3 \) is connected to resistor \( R_2 \) and resistor \( R_4 \) (4Ω). - Node \( V_2 \) is also connected to ground via resistor \( R_3 \) (7Ω). **Circuit Configuration:** - The current source \( I_1 \) is directly feeding into node \( V_2 \). - Node \( V_2 \) is the junction point for all resistors and current sources: - Connected to ground through \( R_3 \) - Connected to node \( V_1 \) through \( R_1 \) - Connected to node \( V_3 \) through \( R_2 \) and \( R_4 \) - The circuit forms a closed loop, ensuring continuity for current flow. This example serves as a practice case for students to apply the nodal analysis technique that helps in finding the potential difference across different points in an electrical circuit.
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