6x3 +7x2 + 20x + 16 Consider the indefinite integral 24 + 4x2 Then the integrand has partial fractions decomposition a cz + d x2 + 4 where a = 4 b =5 C = 1 d = 3 Integrating term by term, we obtain that (6x + 71 + 20x + 16 4 + 4x2 In(2 + 4) x +C of

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A: Given expression, x-14x-2x=5

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Q: 3 +10x?+3x+36 dx (z-1)(z²+4)²

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