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6x + y² = 16, x = y

6x + y² = 16, x = y

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Set up the intergral, and find the area of the region.

The equation depicted is: \[ 6x + y^2 = 16, \quad x = y \] This mathematical expression consists of two components: 1. **Equation**: \(6x + y^2 = 16\) - The term \(6x\) represents six times the variable \(x\). - The term \(y^2\) denotes the square of the variable \(y\). - These terms are added together and set equal to 16. 2. **Condition**: \(x = y\) - This indicates that the variables \(x\) and \(y\) are equal. By substituting \(x = y\) into the equation, it becomes a single-variable equation to solve.
Transcribed Image Text:The equation depicted is: \[ 6x + y^2 = 16, \quad x = y \] This mathematical expression consists of two components: 1. **Equation**: \(6x + y^2 = 16\) - The term \(6x\) represents six times the variable \(x\). - The term \(y^2\) denotes the square of the variable \(y\). - These terms are added together and set equal to 16. 2. **Condition**: \(x = y\) - This indicates that the variables \(x\) and \(y\) are equal. By substituting \(x = y\) into the equation, it becomes a single-variable equation to solve.
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