6x Evaluate / dx using algebraic substitution. (5-x) 2 ® - 10 (A) +C (5-x)3 5-x 10 (B) 2 +C (5-x) 3/2 (5-х) 12 20 12 +C (5-x)3 (5-x)2 none of these 20 12 (E) (5-x) 3/2 (5-x) 1/2 +C

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