6k 6k 6k D. 4 k- 10 ft B - s t-5 ft-- 5 ft--5 ft- EA = constant E = 29,000 ksi A = 6 in.2 FIG. P7.8, P7.56
6k 6k 6k D. 4 k- 10 ft B - s t-5 ft-- 5 ft--5 ft- EA = constant E = 29,000 ksi A = 6 in.2 FIG. P7.8, P7.56
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Use the virtual work method to determine the horizontal deflection at joint E of the truss shown in Fig. P7.8.
Transcribed Image Text:6k
6k
6k
D.
4 k-
10 ft
B
- s t-5 ft-- 5 ft--5 ft-
EA = constant
E = 29,000 ksi
A = 6 in.2
FIG. P7.8, P7.56
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