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6ive the reason for to this lineor equation. Eoch is for coch step of this solution propority of ra honabs 34+ Se 32 Civen -SE Q (34+5)+ (-5) = 32+(-5) 34+(5+ -S) = 32 t (-5) う+。 32 +(-5) 37 to o 32t(-3) 32 t (-5) 3- ミ 27 ()ca= (Y3) (3)4)= (/3)(2) I4)=(113)(27) to (r3)/27) (Y3) (27)

6ive the reason for to this lineor equation. Eoch is for coch step of this solution propority of ra honabs 34+ Se 32 Civen -SE Q (34+5)+ (-5) = 32+(-5) 34+(5+ -S) = 32 t (-5) う+。 32 +(-5) 37 to o 32t(-3) 32 t (-5) 3- ミ 27 ()ca= (Y3) (3)4)= (/3)(2) I4)=(113)(27) to (r3)/27) (Y3) (27)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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6ire the reason for coch step of this solution properity of ra Hunals to this lineor equation. Eoch is o Civen 34+ Se 32 -S E Q (34+5)+ (-5) = 32+(-S) 34+(54 -S) = 32 t (-5) う++。 32 +(-5) 37 to • 32 t(-3) 37=32 t (-5) 3- ミ 27 もEa (ろ)c (13) (27) (Y3) (s)4)=(/3)(27 ) (4)-(13) (2ネ) (132ネ) こ
Transcribed Image Text:6ire the reason for coch step of this solution properity of ra Hunals to this lineor equation. Eoch is o Civen 34+ Se 32 -S E Q (34+5)+ (-5) = 32+(-S) 34+(54 -S) = 32 t (-5) う++。 32 +(-5) 37 to • 32 t(-3) 37=32 t (-5) 3- ミ 27 もEa (ろ)c (13) (27) (Y3) (s)4)=(/3)(27 ) (4)-(13) (2ネ) (132ネ) こ
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