+6e -4e Fig 21-12(1) Two conducting spheres are brought into contact. When they are touching each other, what is the charge in Coulombs on the left- most sphere? i C
+6e -4e Fig 21-12(1) Two conducting spheres are brought into contact. When they are touching each other, what is the charge in Coulombs on the left- most sphere? i C
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Question
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The diagram shows two spheres depicted as purple circles. The left sphere is labeled with a charge of +6e, and the right sphere is labeled with a charge of -4e.
**Understanding Charges:**
1. **Initial Conditions:**
- Left sphere: +6e
- Right sphere: -4e
2. **When Brought into Contact:**
- When the spheres touch, charge redistribution occurs until they reach electrostatic equilibrium.
3. **Total Initial Charge:**
- Total initial charge: +6e + (-4e) = +2e
4. **Charge Redistribution:**
- Assuming the spheres are identical, the charge will be evenly distributed between the two spheres.
- Therefore, each sphere will have a charge of:
\( \frac{+2e}{2} = +1e \)
**Answer Box:**
The left-most sphere will have a charge of:
\[ \text{Charge} = \boxed{+1e} \]
Note: If 'e' represents the elementary charge (approximately \( 1.602 x 10^{-19} \) Coulombs), you can convert this value into Coulombs as needed. For the purpose of this problem, we denote charge in terms of elementary charges 'e'.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12c62ea9-2423-4a35-a6cd-74646c6bbd41%2F51626473-9240-4e7c-a4cf-37666b14dcef%2Fpqglauaa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Charge Redistribution in Conducting Spheres**
**Question:**
Two conducting spheres are brought into contact. When they are touching each other, what is the charge in Coulombs on the left-most sphere?
**Explanation and Figure:**
)
The diagram shows two spheres depicted as purple circles. The left sphere is labeled with a charge of +6e, and the right sphere is labeled with a charge of -4e.
**Understanding Charges:**
1. **Initial Conditions:**
- Left sphere: +6e
- Right sphere: -4e
2. **When Brought into Contact:**
- When the spheres touch, charge redistribution occurs until they reach electrostatic equilibrium.
3. **Total Initial Charge:**
- Total initial charge: +6e + (-4e) = +2e
4. **Charge Redistribution:**
- Assuming the spheres are identical, the charge will be evenly distributed between the two spheres.
- Therefore, each sphere will have a charge of:
\( \frac{+2e}{2} = +1e \)
**Answer Box:**
The left-most sphere will have a charge of:
\[ \text{Charge} = \boxed{+1e} \]
Note: If 'e' represents the elementary charge (approximately \( 1.602 x 10^{-19} \) Coulombs), you can convert this value into Coulombs as needed. For the purpose of this problem, we denote charge in terms of elementary charges 'e'.
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