**Understanding Charge Redistribution in Conducting Spheres****Question:**Two conducting spheres are brought into contact. When they are touching each other, what is the charge in Coulombs on the left-most sphere?**Explanation and Figure:**![Diagram of Conducting Spheres](Fig. 21-12(1))The diagram shows two spheres depicted as purple circles. The left sphere is labeled with a charge of +6e, and the right sphere is labeled with a charge of -4e.**Understanding Charges:**1. **Initial Conditions:** - Left sphere: +6e - Right sphere: -4e2. **When Brought into Contact:** - When the spheres touch, charge redistribution occurs until they reach electrostatic equilibrium. 3. **Total Initial Charge:** - Total initial charge: +6e + (-4e) = +2e4. **Charge Redistribution:** - Assuming the spheres are identical, the charge will be evenly distributed between the two spheres. - Therefore, each sphere will have a charge of: \( \frac{+2e}{2} = +1e \)**Answer Box:**The left-most sphere will have a charge of:\[ \text{Charge} = \boxed{+1e} \]Note: If 'e' represents the elementary charge (approximately \( 1.602 x 10^{-19} \) Coulombs), you can convert this value into Coulombs as needed. For the purpose of this problem, we denote charge in terms of elementary charges 'e'.

When the conductors touch, the charges flow between them. The net charge will be shared between the…

Answered: +6e -4e Fig 21-12(1) Two conducting…

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+6e -4e Fig 21-12(1) Two conducting spheres are brought into contact. When they are touching each other, what is the charge in Coulombs on the left- most sphere? i C