6C4 6P4 .

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem: Evaluate the Expression**

\[
\frac{{^6C_4}}{{^6P_4}}
\]

**Options:**

- A. \( 24 \)
- B. \( 4 \)
- C. \( \frac{1}{24} \)
- D. \( \frac{1}{4} \)

**Explanation:**

- **Combinations \( ^nC_r \):** This represents the number of ways to choose \( r \) items from \( n \) items without regard to order. The formula is:

  \[
  ^nC_r = \frac{n!}{r!(n-r)!}
  \]

- **Permutations \( ^nP_r \):** This represents the number of ways to choose \( r \) items from \( n \) items with regard to order. The formula is:

  \[
  ^nP_r = \frac{n!}{(n-r)!}
  \]

In the problem, substitute \( n = 6 \) and \( r = 4 \) into the formulas for combinations and permutations to evaluate the expression.
Transcribed Image Text:**Problem: Evaluate the Expression** \[ \frac{{^6C_4}}{{^6P_4}} \] **Options:** - A. \( 24 \) - B. \( 4 \) - C. \( \frac{1}{24} \) - D. \( \frac{1}{4} \) **Explanation:** - **Combinations \( ^nC_r \):** This represents the number of ways to choose \( r \) items from \( n \) items without regard to order. The formula is: \[ ^nC_r = \frac{n!}{r!(n-r)!} \] - **Permutations \( ^nP_r \):** This represents the number of ways to choose \( r \) items from \( n \) items with regard to order. The formula is: \[ ^nP_r = \frac{n!}{(n-r)!} \] In the problem, substitute \( n = 6 \) and \( r = 4 \) into the formulas for combinations and permutations to evaluate the expression.
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