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67. y = (2e³x + 3e-2x)4

67. y = (2e³x + 3e-2x)4

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The question asks for you to use the chain rule to solve. Problems 67 and 69 Thanks!
3x+9)-4/3 20 mu +41) + sin x 67. y = (2e³x + 3e-2x)4 aughisted 69. y = e(x²+2x+3)² SECTION 71. y = √√1+√1+√x 73. y = (kx + b)-1/3; k and b cons 1 √kt4 + b In Exercises 75-78, compute the hig d² 75. sin(x²) dx² 74. y = =;k and b consta
Transcribed Image Text:3x+9)-4/3 20 mu +41) + sin x 67. y = (2e³x + 3e-2x)4 aughisted 69. y = e(x²+2x+3)² SECTION 71. y = √√1+√1+√x 73. y = (kx + b)-1/3; k and b cons 1 √kt4 + b In Exercises 75-78, compute the hig d² 75. sin(x²) dx² 74. y = =;k and b consta
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