The following data represent the commute time (in minutes) x and a score on a well-being survey y. The equation of the least-squares regression line is y = - 0.0423x + 69.1961 and the standard error of the estimate is 0.5262. Complete parts (a) through (e) below.152535456082115 D69.0 68.366.8 66.2 66.5 64.2y67.4(a) Predict the mean well-being index composite score of all individuals whose commute time is 30 minutes.y = (Round to two decimal places as needed.)(b) Construct a 90% confidence interval for the mean well-being index composite score of all individuals whose commute time is 30 minutes.Lower Bound(Round to two decimal places as needed.)Upper Bound|(Round to two decimal places as needed.)(c) Predict the well-being index composite score of Jane, whose commute time is 30 minutes.y =(Round to two decimal places as needed.)

Given Out put from Excel format Regression equation Data >> Data analysis >> select…

Answered: 66.8 66.2 66.5 64.2 ex composite score…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Number 11
Graph this data in excel using a statistical test with Count, mean, standard deviation, standard error, Basic statistical summaries: Degrees of freedomT-test, chi-squared test, F-test as needed. Probability
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A marketing analyst wishes to see whether there is a difference in the average time a customer has to wait in a checkout line in three supermarkets in Batangas City.PureGold Walter Mart SM 3 5 1 2 8 3 5 9 4 6 6 2 3 2 7 1 5 3At 0.05 level of significance, is there a significant difference in the mean waiting times of customers for each store? Use 4 decimal placesSTATISTICS = _____COMPUTED VALUE = _____TABULAR VALUE = _____CONCLUSION = _____
I'm completely lost on how to get started with part A, I'm used to being given a mean and deviation. The first drop down menu saids above or below, second saids mean or median. Thank you ahead of time.
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During the 2003 season, Major League Baseball took steps to speed up the play of baseball games in order to maintain fan interest (CNN Headline News, September 30, 2003). The following results come from a sample of 60 games played during the summer of 2002 and a sample of 50 games played during the summer of 2003. The sample mean shows the mean duration of the games included in each sample. 2002 Season 2003 Season n1 = 60 n2 = 50 x1 = 2 hours, 52 minutes x2 = 2 hours, 46 minutes Provide a 95% confidence interval estimate of the reduction in the mean duration of games during the 2003 season.
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A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 239.7-cm and a standard deviation of 0.8-cm. For shipment, 5 steel rods are bundled together.Find P58, which is the average length separating the smallest 58% bundles from the largest 42% bundles. P58 = -cmEnter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
*PLEASE show in excel A different investigator conducts a second study to investigate whether there is a difference in mean PEF in children with chronic bronchitis as compared to those without. Data on PEF are collected and summarized below. Based on the data, is there statistical evidence of a lower mean PEF in children with chronic bronchitis as compared to those without? Run the appropriate test at a=0.05. Group Number of Children Mean PEF Std Dev PEF Chronic Bronchitis 25 281 68 No Chronic Bronchitis 25 319 74 Step 1. Set up hypotheses and determine level of significance. Ho: H1: alpha: Step 2. Select the appropriate test statistic and give its formula. Step 3. Set up decision rule. Step 4. Compute the test statistic Step 5. Conclusion.
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 143 136 121 129 135 Left arm 167 171 189 139 142 In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? A. H0: μd≠0 H1: μd>0 B. H0: μd=0 H1: μd<0 C. H0: μd=0 H1: μd≠0 Your answer is correct. D. H0: μd≠0 H1: μd=0 Identify the test statistic. t=nothing…
Aassume that adults have iq scores that are normally distributed with a mean of 96.1 and a standard deviation 18.2 findthe first quartile which is the iq score separating the bottom 25% from the top 75% first quartile is

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