**Problem Statement:**In circle H with ∠GHJ = 66° and GH = 10 units, find the length of arc GJ. Round to the nearest hundredth.**Diagram:**The diagram is a circle labeled with points G, H, and J. H is at the center of the circle. The points G and J are on the circumference of the circle. There is a central angle ∠GHJ which measures 66°. The line segment GH is the radius of the circle and is 10 units long.**Solution Explanation:**To find the length of arc GJ:1. **Formula for Arc Length**: The arc length (s) of a circle can be calculated using the formula: \[ s = r \theta \] where \(r\) is the radius and \(\theta\) is the angle in radians.2. **Convert Degrees to Radians**: Convert the given angle from degrees to radians since the formula requires radians: \[ \theta \text{ (in radians)} = \theta \text{ (in degrees)} \times \frac{\pi}{180} \] \(\theta\) = 66° × \(\frac{\pi}{180}\)3. **Calculate in Radians**: \[ \theta = 66 \times \frac{\pi}{180} = \frac{11\pi}{30} \text{ radians} \]4. **Calculate Arc Length**: \[ s = r \times \theta = 10 \times \frac{11\pi}{30} \]5. **Compute the Exact Value**: \[ s = \frac{110\pi}{30} \approx 11.52 \text{ units} \]**Thus, the length of arc GJ, rounded to the nearest hundredth, is approximately 11.52 units.**

Name: **Problem Statement:**In circle H with ∠GHJ = 66° and GH = 10 units,
Uploaded: 2024-03-20T06:46:14.000Z
Channel: Bartleby
Description: **Problem Statement:**In circle H with ∠GHJ = 66° and GH = 10 units, find the length of arc GJ. Round to the nearest hundredth.**Diagram:**The diagram is a circle labeled with points G, H, and J. H is at the center of the circle. The points G and J