(650 m/sec) when (t = 0.9 ms).

A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the equilibrium position with a downward velocity of 8 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second) . Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second. y =

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A 26-pound weight stretches a certain spring 2 feet when the weight and spring are placed in a fluid that resists motion with a force equal to four times the speed. If the weight is stopped at the equilibrium position and then given a velocity of 5 ft / s, find the equation of motion. The DE that models this phenomenon is y "+ Xy '+ (p/l)y = 0, where X is the resistance force of the medium, p is the weight and l the stretch it produces in the spring.

A helicopter with a mass of 10,000 kg takes off straight up at t=0. The thrust of the engine is defined given as a function of time: FT= 95 0.18t- (kN). Where t is in units of seconds. How fast is it rising and what is its elevation at t=4s?

I need solutions to all the calculation s in the image

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A used battery was brought to the workshop and the technician noticed that it had 1 litre of distilled water in it but was fully discharged. The specs sheet for this type of battery states that it is fully charged when the change in distilled water to the change in charge equals to the difference between twice the amount of charge and the actual amount of distilled water existing in the battery For the used battery, derive the differential equation and state the initial condition for the range x= 0(0.2)1.0, then obtain a numerical solution for this equation using Euler’s method.

1- Find the velocity x and the position x as functions of the time t for a particle of mass m, which starts from rest at x =0 and t=0, subject to the following force functions: (a) F, = F. + ct (b) F = F, sin ct (c) F, = F, ed Where F, and c are positive constants.

4) A racquetball player encounters a ball coming towards him at a velocity of 22 m/s and at an angle of 5° below the horizontal. He is able to return the ball at a velocity of 30 m/s at an angle of 15° above the horizontal. The 40 gram racquetball is in contact with the racket for 0.04 s. a) Clearly draw coordinate systems for the incoming and outgoing velocity of the racquetball (there should be two). Write out the necessary transformation arrays. b) Draw an FBD of the racquetball. Compute the magnitude of the force exerted by the racquet on the ball. c) Find the angle between the force and horizontal. [Ans. to Check: 6.99°] „V, = 30 m/s 02 = 15° 0,= 5 V, = 22 m/s 5:58 PM 57°F Mostly sunny 3/6/2022 Type here to search 99+