64 kN • m C D 24 kN/m 2 m2 m2 m B S250 × 52 Draw the shear and bending-moment diagrams for the beam and loading shown and determine the maximum normal stress due to bending. For S250 × 52 section S = 482 × 10³ mm³
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- A reinforced concrete beam has a width of 300mm and a overall depth of 500mm. The beam is simply supported over a span of 5m. Steel strength is 420 Mpa and concrete strength is 28 Mpa concrete cover is 60mm from the steel area, As = 2000mm^2 %3D Determine the maximum factored moment of the beam What is the factored load that the beam can carry Select the correct response: Mu 288.17 KN-m Wu = 92.21Kn/m Mu = 288.17 KN-m Wu = 73.19Kn/m Mu = 320.18 KN-m, Wu = 102.46Kn/m Mu = 288.17 KN-m Wu = 65.86Kn/m50 kN w = 20KN/m A 4m 4m 1. What is the reaction at A of the real beam? 2. In constructing the virtual beam and determining the maximum deflection, where must be the 1-unit load be placed? 3. What is the reaction at the support of the virtual beam? 4. In solving the maximum deflection at midspan, how many portions or segments must the beam be divided so that the real and virtual loadings are continuous in each segment? 5. Consider segment AB of the real beam, with x measured from A, what is the moment equation MAB ? 6. In question 4, what are the limiting values of x? 7. Consider segment AB of virtual beam, with x measured from A, what is the moment equation? 8. Analyzing segment BC of the real beam, with x measured from A, what is the moment equation MBc? 9. In the given beam, if the 50 KN load is moved 2m closer to A and deflection at midspan is desired, how many segments must the beam be divided so that the real and virtual loadings are continuous in each segment? 10. What is the…For the loaded beam shown, using moment - area method. a. Determine the value of El6 at mid span and under the concentrated load t b. Determine the deflection at mid span and under the concentrated load Use = 200 GPa and l=65.0x106 mmª. %3D 24 kN 18 kN/m B |-1.5 m→-1.5 m–- - 3 m
- Three distributed loads act on a beam as shown. The load between A and B increases linearly from 0 to a maximum intensity of wi = 14.9 lb/ft at point B. The load then varies linearly with a different slope to an intensity of w, = 20.4 lb/ft at C. The load intensity in section CD of the beam is constant at wz = 11.9 Ib/ft. For each load region, determine the resultant force and the location of its line of action (distance to the right of A for all cases). W2 BY NC SA 2016 Eric Davishahl Wi W3 B -a- -b- Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 4.90 ft 7.84 ft 3.92 ft The resultant load in region AB is FRI lb and acts ft to the right of A. The resultant load in region BC is Fr2 lb and acts ft to the right of A. The resultant load in region CD is Fr3 lb and acts ft to the right of A.21. Simply supported beam 8 m length has a 2.000 kg load at the center. The flexural stress is 25,000 kPa. Find the section modulus. A. 6,434.56 in3 B. 1,846.56 in3 C. 79.82 in3 D. 95.78 in3The T section is shown in Figure below is the cross-section of a beam. The beam is subjected to a uniform distributed load = 4 kN/m. The N.A is located at 34.7 mm from the bottom and that IxA =10.64x106 mm. Determine (a) the maximum shearing suess (b) the shearing stress at 15 mm from the bottom face. Q2 %3D 20mm 4 kN/m 120mm A 34.7 mm 20mm lm 3m 1m 220mm TT
- Consider the same beam (orientation a) in Q1. If b=20 cm and h = 10 cm, and if the beam material has a maximum allowable stress of 100 MPa, then what is the maximum bending moment the beam can be exposed to? b Case (a) OI. 333.33 N.m O II. 20000 N.m III. 33333.33 N.m O IV. 1000 N.m Neutral axisQuestion 4 A steel beam is under 0.006 shear strain. What is the shear stress exerted on the beam if the modulus of rigidity = 83x103 Mpa? Оa. 498 Мра Оb.640 Мра O. 555 Mpa Od. 830 MрaDraw Shear Force Diagram and Bending Moment Diagram for beam below by using Consistent Deformation Method. 7.4 kN A C В 1.2 m 1 m 1 m
- A simple beam of length L = 5 m carries a uniform load of intensity q = 5.8 kN/m and a concentrated load 22.5 kN (see figure). P = 22.5 kN 1.5 m q = 5.8 kN/m -L 5 m- The 1-1 and 2-2 axes are labeled on the cross section below. (a) Assuming oalow = 120 MPa, calculate the required section modulus S (in mm). (At this point, disregard the weight of the beam.) Select the most economical wide-flange beam (W shape) from this table, and recalculate S (in mm), taking into account the weight of the beam. Select a new beam if necessary. mm3 What is the suitable beam size? O w 360 x 79 w 200 x 31.3 O w 360 x 39 O w 250 x 89 O w 200 x 41.7Q/3 The simply supported beam in Figure below has a rectangular 8 kN cross section 120 mm wide and 200 mm high: 2 kN/m 1. Draw shear force and bending moment diagrams. 2. Compute the maximum bending stress in the beam. 13 kN 3. Find the maximum shear stress in the beam. 5m 3m K ( 25 Marks)es/69424/quizzes/321785/take Question 20 2 pts An overhanging beam is subjected to a partial uniform load w = 33 kN/m and two pint loads.P1 = 75 kN, P2 =460 kN. The beam has a hinge support at point %3D %3D B, a horizontal roller support at point A with overhangs on both sides as shown. P2 (kN) w (kN/m) -2 m P1 (kN) What is the vertical reaction in kN at support B, i.e. what is Rgy? Enter a positive value to represent UPWARD reaction and negative value to represent DOWNWARD reaction. 3pts Question 21