63. From the following information, find the standard deviation of x and yvariableΣχ= 235,Σχ2 6750,Σy= 250Ey = 6840%3Dn= 10or Vesgl noltshsv to tneloilleco son2aulilTol stab er gninidnt gyol Brot srat Bot t stot stab Dborelamol pnsielmjo aquorebuolecrwoniwollol erfT 30

Answered: Image /qna-images/answer/3ab89df3-d2fb-4b9a-9771-d2ffcd6fdd9d.jpg

Answered: 63. From the following information,…

MATLAB: An Introduction with Applications

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ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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a b Absolute standard deviation = Coefficient of variation = y = 1.20 (+0.02) x 10-8-3.60(±0.2) × 10-⁹ x Result = Absolute standard deviation = Coefficient of variation = C Result = d y=90.95 (±0.08) - 89.40(±0.06) +0.200(+0.004) Absolute standard deviation == Coefficient of variation = Result = ± y= y = 0.0040 (+0.0005) x 10.28 (+0.02) × 395(+1) Result = ± Absolute standard deviation = Coefficient of variation = % 329(+0.03) x 10-14 1.47 (+0.04) x 10-16 % % H % ±
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63. From the following information, find the standard deviation of xand y variable Σx= 235, Ex2 = 6750, Σy= 250 Ey = 6840 n= 10 Ves