Please make sure you answer all of it it is all one question ## Question 861% of all Americans are homeowners. If 34 Americans are randomly selected, find the probability that:a. Exactly 22 of them are homeowners. [ ]b. At most 20 of them are homeowners. [ ]c. At least 20 of them are homeowners. [ ]d. Between 15 and 21 (including 15 and 21) of them are homeowners. [ ]**Hint:**- Hint [link]- Video on Finding Binomial Probabilities [link][Submit Question]

Name: Please make sure you answer all of it it is all one question ## Questi
Uploaded: 2024-03-05T11:52:21.000Z
Channel: Bartleby
Description: Please make sure you answer all of it it is all one question ## Question 861% of all Americans are homeowners. If 34 Americans are randomly selected, find the probability that:a. Exactly 22 of them are homeowners. [ ]b. At most 20 of them are homeown

Given that, Sample size of Americans n=34 Probability of Americans who are home owners p=0.61a. Probability that exactly 22 of them are home owners: The probability that exactly 22 of them are home owners can be calculated as follows: PX=22=PX-npnp1-p=22-npnp1-p=Pz=22-34×0.6134×0.61×0.39=Pz=22-20.742.84405=Pz=0.44=0.6700b. Probability that at most 20 of them are home owners: The probability that at most 20 of them are home owners can be calculated as follows: PX≤20=PX-npnp1-p≤20-npnp1-p=Pz≤20-34×0.6134×0.61×0.39=Pz≤20-20.742.84405=Pz≤-0.26=0.3974c. Probability that at least 20 of them are home owners: The probability that at least 20 of them are home owners can be calculated as follows: PX≥20=PX-npnp1-p≥20-npnp1-p=Pz≥20-34×0.6134×0.61×0.39=Pz≥20-20.742.84405=Pz≥-0.26=Pz<0.26=0.6026d. Probability that between 15 and 21 of them are home owners: The probability that between 15 and 21 of them are home owners can be calculated as follows: P15≤X≤21=P15-npnp1-p≤X-npnp1-p≤21-npnp1-p=P15-34×0.6134×0.61×0.39≤z≤21-34×0.6134×0.61×0.39=P15-20.742.84405≤z≤21-20.742.84405=P-2.02≤z≤0.09=Pz≤0.09-Pz≤-2.02=0.5359-0.0217=0.5142