61. Anhydrous chromium(III) chloride, CrCl3, is prepared by reacting Cr₂O3 with CCl4 at 800°C. Identify the limiting reagent (LR) and calculate the number of grams left over of the reagent in excess, given 10.0 g of Cr₂O3 and 24.0 g of CCl4. Cr₂O3 + 3CCl4 → 2CrCl3 + 3 COCI₂ a. LR CCl4, 2.1 g Cr₂O3 d. LR Cr₂O3, 3.70 g CCl4 b. LR CCl4, 3.70 g Cr₂O3 c. LR Cr₂O3, 10.0 g CCl4 e. LR Cr₂O3, 6.75 g CCl4

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61. Anhydrous chromium(III) chloride, CrCl3, is prepared by reacting Cr₂O3 with CCl4 at 800°C. Identify
the limiting reagent (LR) and calculate the number of grams left over of the reagent in excess, given 10.0
g of Cr₂O3 and 24.0 g of CCl4. Cr₂O3 + 3CCl4 → 2CrCl3 + 3 COCI₂
a. LR CCl4, 2.1 g Cr₂O3
d. LR Cr₂O3, 3.70 g CCl4
b. LR CCl4, 3.70 g Cr₂O3
c. LR Cr₂O3, 10.0 g CCl4
e. LR Cr₂O3, 6.75 g CCl4
Transcribed Image Text:61. Anhydrous chromium(III) chloride, CrCl3, is prepared by reacting Cr₂O3 with CCl4 at 800°C. Identify the limiting reagent (LR) and calculate the number of grams left over of the reagent in excess, given 10.0 g of Cr₂O3 and 24.0 g of CCl4. Cr₂O3 + 3CCl4 → 2CrCl3 + 3 COCI₂ a. LR CCl4, 2.1 g Cr₂O3 d. LR Cr₂O3, 3.70 g CCl4 b. LR CCl4, 3.70 g Cr₂O3 c. LR Cr₂O3, 10.0 g CCl4 e. LR Cr₂O3, 6.75 g CCl4
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