•61 SSM The function (x) displayed in Eq. 38-27 can describe a free particle, for which the potential energy is U(x) = 0 in Schrödinger's equation (Eq. 38-19). Assume now that U(x) = U, = a constant in that equation. Show that Eq. 38-27 is a solution of Schrödinger's equation, with %3D -V2m(E – U) giving the angular wave number k of the particle. k k =

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•61 SSM The function (x) displayed in Eq. 38-27 can describe a
free particle, for which the potential energy is U(x) = 0 in
Schrödinger's equation (Eq. 38-19). Assume now that U(x) = U, =
a constant in that equation. Show that Eq. 38-27 is a solution of
Schrödinger's equation, with
%3D
-V2m(E – U)
giving the angular wave number k of the particle.
k
k =
Transcribed Image Text:•61 SSM The function (x) displayed in Eq. 38-27 can describe a free particle, for which the potential energy is U(x) = 0 in Schrödinger's equation (Eq. 38-19). Assume now that U(x) = U, = a constant in that equation. Show that Eq. 38-27 is a solution of Schrödinger's equation, with %3D -V2m(E – U) giving the angular wave number k of the particle. k k =
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