= = (600.2) (1110.8889 μA²) 225 V2 + 300 Ω = 0.666 W + 0.75 W Total power absorbed = 1.416 W
= = (600.2) (1110.8889 μA²) 225 V2 + 300 Ω = 0.666 W + 0.75 W Total power absorbed = 1.416 W
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter7: Alternating Current, Power Distribution, And Voltage Systems
Section: Chapter Questions
Problem 12RQ
Question
how do we get .666 and .75 watts from this?

Transcribed Image Text:=
= (600.2) (1110.8889 μA²)
225 V2
+
300 Ω
= 0.666 W + 0.75 W
Total power absorbed
= 1.416 W
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images

Recommended textbooks for you

Electricity for Refrigeration, Heating, and Air C…
Mechanical Engineering
ISBN:
9781337399128
Author:
Russell E. Smith
Publisher:
Cengage Learning

Electricity for Refrigeration, Heating, and Air C…
Mechanical Engineering
ISBN:
9781337399128
Author:
Russell E. Smith
Publisher:
Cengage Learning