= = (600.2) (1110.8889 μA²) 225 V2 + 300 Ω = 0.666 W + 0.75 W Total power absorbed = 1.416 W

7,00 mH 2,00N a b. 3,00 2 9,002 5,00 N 5,00 N 11,0N 3,00 V 1,00 N S g h

15 kN 60 V 75 kM +

The frequency of this voltage source is V(mV) 238 136 34 I I 10 10 Hz 20 Hz 50 Hz 60 Hz 720 t(ms)

QUESTION 7 An industrial heater has a nameplate that reads: 166 Vrms 50 Hz 106 KVA 0.88 lagging What is the apparent power? Write your answer in kVA. QUESTION 8 An industrial heater has a nameplate that reads: 128 Vrms 69 Hz 155 KVA 0.75 lagging What is the real power? Write your answer in Watts. QUESTION 9 An industrial heater has a nameplate that reads: 219 Vrms 50 Hz 106 kVA 0.82 lagging What is the reactive power? Write your answer in VAR.

#19

Given the circuit shown, Calculate the Peak Output Voltage. Express your answers in two decimal places (i.e., 9.946 becomes 9.95, and 7.6 becomes 7.60). 4:1 D1 120 V rms RL 1.0 kN D2 elle lelll

sketch the relation between  IZ and IL  (Use graph paper)

Can you help me solve this question?

18. If the rms value of AC current through a 10 k2 resistor is 5 mA, the rms value of voltage drop across the resistor is (a) 70.7V (b) 7.07V (c) 5V (d) 50 V