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*60. Use scientific conventions and mathematical procedures, including scientific notation, to express each of the rounded-off answers in Problems 58 and 59 in scientific notation.

*60. Use scientific conventions and mathematical procedures, including scientific notation, to express each of the rounded-off answers in Problems 58 and 59 in scientific notation.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Please help me on question 60
er the ht. ep e ne. 58. Express the following quantities using scientific conventions and mathematical procedures, including significant figures, to round off each of these measurements to three significant figures. a. 98.473 L b. 0.000 763 21 cg c. 57.048 m d. 12.17°C e. 0.007 498 3 × 104 mm f. 1764.9 mL *59. Round off each of the answers correctly. a. 8.7 g +15.43 g + 19 g = 43.13 g b. 4.32 cm X 1.7 cm = 7.344 cm² - c. 853.2 L 627.443 L = 225.757 L d. 38.742 m² + 0.421 m 92.023 75 m e. 5.40 m X 3.21 m X 1.871 m = 32.431 914 m³ f. 5.47 m³ + 11 m³ + 87.300 m³ = 103.770 m³ = *60. Use scientific conventions and mathematical procedures, including scientific notation, to express each of the rounded-off answers in Problems 58 and 59 in scientific notation.
Transcribed Image Text:er the ht. ep e ne. 58. Express the following quantities using scientific conventions and mathematical procedures, including significant figures, to round off each of these measurements to three significant figures. a. 98.473 L b. 0.000 763 21 cg c. 57.048 m d. 12.17°C e. 0.007 498 3 × 104 mm f. 1764.9 mL *59. Round off each of the answers correctly. a. 8.7 g +15.43 g + 19 g = 43.13 g b. 4.32 cm X 1.7 cm = 7.344 cm² - c. 853.2 L 627.443 L = 225.757 L d. 38.742 m² + 0.421 m 92.023 75 m e. 5.40 m X 3.21 m X 1.871 m = 32.431 914 m³ f. 5.47 m³ + 11 m³ + 87.300 m³ = 103.770 m³ = *60. Use scientific conventions and mathematical procedures, including scientific notation, to express each of the rounded-off answers in Problems 58 and 59 in scientific notation.
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