6.A Three identical capacitors are connected as shown. You charge the capacitors by attaching batteries to points A, B and C (but not D). You then disconnect the batteries to find that the potential at point A is Va=100V, at point B is Vb=60V, and at point C is Vc=50V. The potential at point D is then: A B a) (Va * Vb + Vc * Vb)2 b) (Va + Vb + Vc)/3 c) (Va + Vc- Vb)/2 d) Va/100+Vb/60+Vc/50 e) Va*100+Vb*60+Vc*50 ) Va*Vb*Vc
6.A Three identical capacitors are connected as shown. You charge the capacitors by attaching batteries to points A, B and C (but not D). You then disconnect the batteries to find that the potential at point A is Va=100V, at point B is Vb=60V, and at point C is Vc=50V. The potential at point D is then: A B a) (Va * Vb + Vc * Vb)2 b) (Va + Vb + Vc)/3 c) (Va + Vc- Vb)/2 d) Va/100+Vb/60+Vc/50 e) Va*100+Vb*60+Vc*50 ) Va*Vb*Vc
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![6.A Three identical capacitors are connected as shown. You charge the
capacitors by attaching batteries to points A, B and C (but not D). You
then disconnect the batteries to find that the potential at point A is
Va=100V, at point B is Vb=60V, and at point C is Vc=50V. The potential
at point D is then:
A
bove
D.
a) (Va * Vb + Vc * Vb)'2
b) (Va + Vb + Vc)/3
c) (Va + Vc- Vb)/2
d) Va/100+Vb/60+Vc/50
e) Va*100+Vb*60+Vc*50
f) Va*Vb*Vc
°.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee043644-8c82-4555-bd39-471becdabd6c%2Fae9ab2ff-f3f7-455e-93b4-d2be8221f072%2F7pd5fsv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6.A Three identical capacitors are connected as shown. You charge the
capacitors by attaching batteries to points A, B and C (but not D). You
then disconnect the batteries to find that the potential at point A is
Va=100V, at point B is Vb=60V, and at point C is Vc=50V. The potential
at point D is then:
A
bove
D.
a) (Va * Vb + Vc * Vb)'2
b) (Va + Vb + Vc)/3
c) (Va + Vc- Vb)/2
d) Va/100+Vb/60+Vc/50
e) Va*100+Vb*60+Vc*50
f) Va*Vb*Vc
°.
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