6.8. Liquid isobutane is throttled through a valve from an initial state of 360 K and 4000 kPa to a final pressure of 2000 kPa. Estimate the temperature change and the entropy change of the isobutane. The specific heat of liquid isobutane at 360 K is 2.78 J.g-¹.°C-1. Estimates of V and ß may be found from Eq. (3.68).
6.8. Liquid isobutane is throttled through a valve from an initial state of 360 K and 4000 kPa to a final pressure of 2000 kPa. Estimate the temperature change and the entropy change of the isobutane. The specific heat of liquid isobutane at 360 K is 2.78 J.g-¹.°C-1. Estimates of V and ß may be found from Eq. (3.68).
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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
Transcribed Image Text:6.8. Liquid isobutane is throttled through a valve from an initial state of 360 K and
4000 kPa to a final pressure of 2000 kPa. Estimate the temperature change and the
entropy change of the isobutane. The specific heat of liquid isobutane at 360 K is
2.78 J.g-¹.°C-1. Estimates of V and ß may be found from Eq. (3.68).
![In addition, generalized equations are available for the estimation of molar volumes of
saturated liquids. The simplest equation, proposed by Rackett, 22 is an example:
Vsat = = VcZc (1-T,)2/7
An alternative form of this equation is sometimes useful:
Zsat = Prz[1+(1-7,2/7]
Tr
(3.68)
(3.69)
22H. G. Rackett, J. Chem. Eng. Data, vol. 15, pp. 514-517, 1970; see also C. F. Spencer and S. B. Adler, ibid.,
vol. 23, pp. 82-89, 1978, for a review of available equations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63f5865a-7713-44c4-be73-1c5678c4385b%2Fa5c07e56-d7bf-41f6-88c0-b83a95fa944e%2Fiall79c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In addition, generalized equations are available for the estimation of molar volumes of
saturated liquids. The simplest equation, proposed by Rackett, 22 is an example:
Vsat = = VcZc (1-T,)2/7
An alternative form of this equation is sometimes useful:
Zsat = Prz[1+(1-7,2/7]
Tr
(3.68)
(3.69)
22H. G. Rackett, J. Chem. Eng. Data, vol. 15, pp. 514-517, 1970; see also C. F. Spencer and S. B. Adler, ibid.,
vol. 23, pp. 82-89, 1978, for a review of available equations.
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