Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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X X
Sun Aug 8 7:42 PM
Theodore E. Brown, H. Eugene H LeMay, Bruce E. Bursten, Cather...
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mate. In this case the pH, as we predicted, falls between 6 and 5. Had
the calculated pH and the estimate not agreed, we should have recon-
sidered our calculation or estimate or both.
Ch
Theodore E. Brown, H. Eu...
Because 1.0 X 10-12 has two significant figures, the pH has two
decimal places, 12.00.
Is
ri
MIRKIN
Cell m
he pH Scale
The I mn tu
air n
opert
mi N d
682
CHAPTER 16 Acid-Base Equilibria
680
Practice Exercise 1
Practice Exercise 2
A solution at 25 °C has [OH¯]
the solution?
(a) In a sample of lemon juice, [H*]
(b) A commonly available window-cleaning solution has
[OH] = 1.9 × 10-6 M. What is the pH at 25 °C?
6.7 X 103. What is the pH of
= 3.8 X 104 M. What is the pH?
T H1 r HU nd T
(a) 0.83 (b) 2.2 (c) 2.17
(d) 11.83 (e) 12
Srrer ma v m e
e n
o m 'i eerfi e
o al
RK -- -
dm siee
pOH and Other "p" Scales
s HIdab akcer
Crigger Feeli
Love Withi
rerTett taTR
The negative logarithm is a convenient way of expressing the magnitudes of other small
quantities. We use the convention that the negative logarithm of a quantity is labeled
"p" (quantity). Thus, we can express the concentration of OH as pOH:
РОН 3 - 1og[ОН]
AGe Sa Th
ea L g r
e d
Derpte
[16.18]
l
ttn I
Likewise, pK„ equals –log Kw.
By taking the negative logarithm of both sides of the equilibrium-constant expres-
sion for water, Kw
Male
Exp
681
[H*][OH¯], we obtain
-log[H*]+ (-log [OH ]) = -log Kw
[16.19]
By: Jam
indne
syser
from which we obtain the useful expression
- H e
PH + рОН 3 14.00 (at 25°C)
[16.20]
pOH and other Seales
T t
girt Rrde
ple am
The pH and pOH values characteristic of a number of familiar solutions are shown in
(V Figure 16.6). Notice that a change in [H*] by a factor of 10 causes the pH to change by 1.
Thus, the concentration of H* (ag) in a solution of pH 5 is 10 times the H* (aq) concentra-
tion in a solution of pH 6.
poigoel oea
e
Th r el
conau
PI rias
GO FIGURE
PDF
Which is more acidic, black coffee or lemon juice?
Light
[H*] (M)
pH
РОН [ОН] (M)
682
-14
1 (1×10º)
0.0
14.0
1X10
AUG
8.
étv A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffcbd669c-f16c-4186-8647-cce1c8793c67%2F8f85a842-288f-4b32-b1c4-93317398a46d%2Fdlmeo2_processed.png&w=3840&q=75)
Transcribed Image Text:Preview
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X X
Sun Aug 8 7:42 PM
Theodore E. Brown, H. Eugene H LeMay, Bruce E. Bursten, Cather...
Page 721 of 1,246 – Shared
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mate. In this case the pH, as we predicted, falls between 6 and 5. Had
the calculated pH and the estimate not agreed, we should have recon-
sidered our calculation or estimate or both.
Ch
Theodore E. Brown, H. Eu...
Because 1.0 X 10-12 has two significant figures, the pH has two
decimal places, 12.00.
Is
ri
MIRKIN
Cell m
he pH Scale
The I mn tu
air n
opert
mi N d
682
CHAPTER 16 Acid-Base Equilibria
680
Practice Exercise 1
Practice Exercise 2
A solution at 25 °C has [OH¯]
the solution?
(a) In a sample of lemon juice, [H*]
(b) A commonly available window-cleaning solution has
[OH] = 1.9 × 10-6 M. What is the pH at 25 °C?
6.7 X 103. What is the pH of
= 3.8 X 104 M. What is the pH?
T H1 r HU nd T
(a) 0.83 (b) 2.2 (c) 2.17
(d) 11.83 (e) 12
Srrer ma v m e
e n
o m 'i eerfi e
o al
RK -- -
dm siee
pOH and Other "p" Scales
s HIdab akcer
Crigger Feeli
Love Withi
rerTett taTR
The negative logarithm is a convenient way of expressing the magnitudes of other small
quantities. We use the convention that the negative logarithm of a quantity is labeled
"p" (quantity). Thus, we can express the concentration of OH as pOH:
РОН 3 - 1og[ОН]
AGe Sa Th
ea L g r
e d
Derpte
[16.18]
l
ttn I
Likewise, pK„ equals –log Kw.
By taking the negative logarithm of both sides of the equilibrium-constant expres-
sion for water, Kw
Male
Exp
681
[H*][OH¯], we obtain
-log[H*]+ (-log [OH ]) = -log Kw
[16.19]
By: Jam
indne
syser
from which we obtain the useful expression
- H e
PH + рОН 3 14.00 (at 25°C)
[16.20]
pOH and other Seales
T t
girt Rrde
ple am
The pH and pOH values characteristic of a number of familiar solutions are shown in
(V Figure 16.6). Notice that a change in [H*] by a factor of 10 causes the pH to change by 1.
Thus, the concentration of H* (ag) in a solution of pH 5 is 10 times the H* (aq) concentra-
tion in a solution of pH 6.
poigoel oea
e
Th r el
conau
PI rias
GO FIGURE
PDF
Which is more acidic, black coffee or lemon juice?
Light
[H*] (M)
pH
РОН [ОН] (M)
682
-14
1 (1×10º)
0.0
14.0
1X10
AUG
8.
étv A
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