6.5.9 Example I Let N be a positive number and consider the following nonlinear difference equation: Yk+1 = /½(Yk – N/Yk). (6.120) Using the fact that cot2 0 (cot (20) = - 1 (6.121) %3D 2 cot 0 we can make the substitution yk VN cot xk, reducing equation (6.120) to the form cot xk+1 = cot (2ak). (6.122) A solution of this latter equation is Xk+1 2xk. (6.123) Therefore, Xk = c2k (6.124) and VN cot(c2*).) (6.125) Yk =

Q: S. S. dy dx

A:

Q: y= ektan

A: y=ek tan x                 y'=ddxe k tan x    =e k tan xddxk tanx…

Q: 3. 3 de dy 40

A:

Q: Kindly answer d,e,f and g

A: Ans- d) Possible reasons why Contractor 2 did not submit a proposal include: Lack of capacity or…

Q: Redo C please

A: .

Q: Find x. * 15 6,

A:

Q: ed 0,

A: The Laplace transform of a function can be obtained by using the Laplace transform table. The…

Q: 33 10

A:

Q: Subtract the lollowing

A:

Q: A= ュC= D=0 FIND AK

A: The given matrix is A=1201213 To find: Ak

Q: dim(M3) %3D O 6 O 3 O 2 O 5 None

A: M23 is the matrix with 2 rows and 3 columns. That is a matrix of order 2×3.

Q: Translate

A: Given point C 1 , 0 After applying conditions in point A ,we get  C1 , 0 → -3 , 0  → -3 ,-4 Now ,…

Q: A= A

A: We will find out the required value.

Q: Use mathematical induction to show that

A:

Q: 3と tz0 ナ2?

A: Given equation,     3t2-4t=0

Q: ease

A: X Y 62 120 62 140 63 130 65 150 66 142 67 130 68 135 68 175 70 149 72 168…

Q: answer d

A: From the  above parts we have  µx̅ = 155σx̅  = 6.75