6.4.1 Еxample Let the function f be equal to (Ayr)²; therefore, equation (6.52) becomes Yk = kx + x, where we have substituted x = Ayk. Operating with A gives (6.61) (k + 1)Aæk + 2xAxk + (Axk)² = 0. (6.62) Thus, we conclude that either
6.4.1 Еxample Let the function f be equal to (Ayr)²; therefore, equation (6.52) becomes Yk = kx + x, where we have substituted x = Ayk. Operating with A gives (6.61) (k + 1)Aæk + 2xAxk + (Axk)² = 0. (6.62) Thus, we conclude that either
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Show me the steps of determine purple and the eqaution is here
![6.4.1 Example
Let the function f be equal to (Ayık)²; therefore, equation (6.52) becomes
= kxk + x%,
(6.61)
where we have substituted xk =
Ayk. Operating with A gives
(k + 1)A¤k + 2x1Axk + (Axk)² = 0.
(6.62)
Thus, we conclude that either
and
Yk
ck + c²,
(6.63)
or
Axk + 2xk + k +1
The solution to the last equation is
Xk+1+ Xk + k + 1= 0.
(6.64)
Xj = c(-1)* – 1/2k – 1/4,
(6.65)
which gives for equation (6.61) the second solution
Yk = [c(-1)* – 1/4]² – 1/¼k².
(6.66)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57a26049-260e-45aa-910f-dd852150673b%2F832e47da-1374-4423-912e-686d7faf3f0d%2Fsu9tbes_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6.4.1 Example
Let the function f be equal to (Ayık)²; therefore, equation (6.52) becomes
= kxk + x%,
(6.61)
where we have substituted xk =
Ayk. Operating with A gives
(k + 1)A¤k + 2x1Axk + (Axk)² = 0.
(6.62)
Thus, we conclude that either
and
Yk
ck + c²,
(6.63)
or
Axk + 2xk + k +1
The solution to the last equation is
Xk+1+ Xk + k + 1= 0.
(6.64)
Xj = c(-1)* – 1/2k – 1/4,
(6.65)
which gives for equation (6.61) the second solution
Yk = [c(-1)* – 1/4]² – 1/¼k².
(6.66)
Transcribed Image Text:ull stc ksa
3:03 PM
C @ 1 40%
As an application of this method considers the Clairaut difference equation
Yk = kAyk + f (Ayk),
(6.52)
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