6.4.1 Example Let the function f be equal to (Ayk)²; therefore, equation (6.52) becomes Yk kak + x%, (6.61) where we have substituted x = Ayk. Operating with A gives (k +1)Ax + 2x 1Axj, + (Axk)² = 0. (6.62) Thus, we conclude that either Axk = 0 and Yk = ck + c², (6.63) or Axk + 2xk + k+1= xk+1+ xk +k +1 = 0. (6.64) The solution to the last equation is ær = c(-1)* – 1/½k – 1/4, (6.65) | which gives for equation (6.61) the second solution Yk = [c(-1)k – 1/4]² – 1¼k?. (6.66)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
icon
Concept explainers
Topic Video
Question

Explain the determine purple and the eqaution is here

6.4.1
Example
Let the function f be equal to (Ayk)²; therefore, equation (6.52) becomes
= kæk + x%,
(6.61)
where we have substituted x, = Ayk. Operating with A gives
(k +1)Axk + 2x1Axk + (Axk)² = 0.
(6.62)
Thus, we conclude that either
and
Yk = ck + c²,
(6.63)
or
Axk + 2xk + k +1
Xk+1+xk+ k +1= 0.
(6.64)
The solution to the last equation is
c(-1)* – 1/2k – 1/4,
(6.65)
Xk
which gives for equation (6.61) the second solution
Yk = [c(-1)* – 1/4]² – 1/¼k?.
(6.66)
Transcribed Image Text:6.4.1 Example Let the function f be equal to (Ayk)²; therefore, equation (6.52) becomes = kæk + x%, (6.61) where we have substituted x, = Ayk. Operating with A gives (k +1)Axk + 2x1Axk + (Axk)² = 0. (6.62) Thus, we conclude that either and Yk = ck + c², (6.63) or Axk + 2xk + k +1 Xk+1+xk+ k +1= 0. (6.64) The solution to the last equation is c(-1)* – 1/2k – 1/4, (6.65) Xk which gives for equation (6.61) the second solution Yk = [c(-1)* – 1/4]² – 1/¼k?. (6.66)
ull stc ksa
3:03 PM
C @ 1 40%
As an application of this method considers the Clairaut difference equation
Yk = kAyk + f (Ayk),
(6.52)
Cancel
Actual Size (434 KB)
Choose
Transcribed Image Text:ull stc ksa 3:03 PM C @ 1 40% As an application of this method considers the Clairaut difference equation Yk = kAyk + f (Ayk), (6.52) Cancel Actual Size (434 KB) Choose
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Sample space, Events, and Basic Rules of Probability
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,