6.3.2 Example B The equation Yk+1Yk + ayYk+1+byk = C, (6.32) where a, b, and c are constants, is of the form given by equation (6.17). Thus, the substitution Yk = Xk/xk+1 – b (6.33) NONLINEAR DIFFERENCE EQUATIONS 199 transforms this equation to the form (ab + c)ak+1 – (a – b)xk – xk-1 = 0. (6.34) The characteristic equation for equation (6.34) is (ab + c)r – (a – b)r – 1= 0. (6.35) If we denote the two roots by rị and r2, then the solution to equation (6.34) can be written Xk = Dırf + Dzr, (6.36) where D1 and D2 are arbitrary constants. Substituting equation (6.36) into equation (6.33) gives (1 – br1) + (1 – br2)D(r2/r1)* ri +D(r2/r1)k+1 Yk = (6.37) where D is an arbitrary constant. This is the general solution of equation (6.32).

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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6.3.2 Example B
The equation
Yk+1Yk + ayk+1+ byk
= c,
(6.32)
where
a,
b, and c are constants, is of the form given by equation (6.17). Thus,
the substitution
Yk
Xk /Xk+1 - 6
(6.33)
NONLINEAR DIFFERENCE EQUATIONS
199
transforms this equation to the form
(ab + c)xk+1 – (a – b)xk – Xk-1 = 0.
(6.34)
The characteristic equation for equation (6.34) is
(ab + c)r2 – (a – b)r – 1 = 0.
(6.35)
If we denote the two roots by rị and r2, then the solution to equation (6.34)
can be written
Xk = Dırf + D2r,
(6.36)
where D1 and D2 are arbitrary constants. Substituting equation (6.36) into
equation (6.33) gives
(1 – br1) + (1 – br2)D(r2/r1)k
ri + D(r2/r1)k+1
Yk
(6.37)
where D is an arbitrary constant. This is the general solution of equation
(6.32).
Transcribed Image Text:6.3.2 Example B The equation Yk+1Yk + ayk+1+ byk = c, (6.32) where a, b, and c are constants, is of the form given by equation (6.17). Thus, the substitution Yk Xk /Xk+1 - 6 (6.33) NONLINEAR DIFFERENCE EQUATIONS 199 transforms this equation to the form (ab + c)xk+1 – (a – b)xk – Xk-1 = 0. (6.34) The characteristic equation for equation (6.34) is (ab + c)r2 – (a – b)r – 1 = 0. (6.35) If we denote the two roots by rị and r2, then the solution to equation (6.34) can be written Xk = Dırf + D2r, (6.36) where D1 and D2 are arbitrary constants. Substituting equation (6.36) into equation (6.33) gives (1 – br1) + (1 – br2)D(r2/r1)k ri + D(r2/r1)k+1 Yk (6.37) where D is an arbitrary constant. This is the general solution of equation (6.32).
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