6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and distances: B A = 38°30' Az. = 306°31' AB = 371.006 m %3D B = 100°38' BC = 110.222 m C = 149°50 CD = 139.872 m %3D N D = 85°59' DE = 103.119 m E = 165°03' EA = 319.860 m FIGURE 6.24 Sketch for Problem 6.16. Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. (d) Compute the linear error of closure and the precision ratio.

6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and distances: B A = 38°30' Az. = 306°31' AB = 371.006 m %3D B = 100°38' BC = 110.222 m C = 149°50 CD = 139.872 m %3D N D = 85°59' DE = 103.119 m E = 165°03' EA = 319.860 m FIGURE 6.24 Sketch for Problem 6.16. Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. (d) Compute the linear error of closure and the precision ratio.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) Interior Angles Departures Latitudes AB 75°14'47" 519.474 A = 12°25'31" 502.34691 132.29066 BC 303°34'09" 456.615 B = 48°19'25" -380.46099 252.48107 CD 250°11'30" 433.926 C = 126°37'24" -408.2521 -147.04419 DE 116°15'03" 427.608 D = 46°03'36" 383.50666 -189.13288 EA 242°49'19" 107.83 E 306°34'19" -95.928244 -49.253868 Ay, By, Cy, Dy, Ey = Submit Request Answer Part E AC = Submit Find the length of line AC. Express your answer in meters to six significant figures. ▾ Part F N 195| ΑΣΦ | 41 Request Answer Submit Π| ΑΣΦ [ΨΕΙ ΑΣΦ | Find the bearing of line AC. Express your answer in degrees to four significant figures. Request Answer vec 11 vec vec wwww. ? ? O m E ?
3. A closed traverse has the following data. Find the bearing of line AB and the length of line BC. Solve for the Area of this traverse using the DPD Method. LINE AB BC CD DE EA DISTANCE 44.47 ? 12.83 64.86 107.72 BEARING ? N57°11'W N1°45'E N72°10'E S 48°13'E
Item 7 The observed lengths of the sides (in feet) of a five-sided closed polygon traverse are as follows: AB=201.74, BC = 283.37, CD=497.87, DE = 321.33, and EA 381.28. (Note: Assume units of feet for all distances.) The preliminary azimuths obtained after balancing the angles are as follows: AB=138° 16'27", BC = 67°02′46", CD = 354°22′24", DE = 256° 13'01", EA = 185°29'20". Submit Part C Compute the linear misclosure. Express your answer in feet to three significant figures. Submit IVE ΑΣΦ ↓↑ vec Part D Request Answer 1: Compute the relative precision. Express your answer to three significant figures. Submit Request Answer AΣ vec Request Answer ? ? ft 7 of 9 Review
The tabulation shown below is the traverse data of a five-sided closed polygon. If the azimuth from the north of side AB is fixed at 74° 31’ 17”, determine the following: (Note: Line BC bears NW.) 1.1 The balanced interior angle A is 105° 13’ 1.2 The balanced interior angle B is 92° 36’ 1.3 The balanced interior angle C is 67° 15’ 1.4 The balanced interior angle D is 217° 24’ 1.5 The balanced interior angle E is 57° 30’
The data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) Interior Angles AB 75°14'47" 519.674 A = 12°25'31" 455.265 B=48°19'25" 433.426 C = 126°37'24" 425.558 BC CD DE D = 46°03'36" 109.434 E = 306° 34'19" EA Part A Compute the preliminary azimuths. AZAB = 57°14'47", Azpc = 303° 34'09", AzcD = 250°11'30". AZDE = 116° 15'03". AZEA = 242° 49'19" AZAB = 75°00'47", Azpc = 303° 00'09", AZCD = 250°00'30", AZDE=116°00'03", AZEA = 242°00'19" AZAB = 75°14'47", AZBC = 313° 34'09", AzcD = 25°11'30", AZDE = 116° 10'00". AZEA = 224°49′19" AZAB = 75°14'47". AzBc = 303° 34'09", Azcp=250°11'30". AZDE = 116°15'03". AZEA = 242° 49'19" Submit Previous Answers ✓ Correct Part B Compute the unadjusted departures. Express your answers in meters to six significant figures and separated by commas. IVD ΑΣΦΠ Vec 6 X Incorrect; Try Again; ? AB. BC. CD. DE. EA= 502.304, 308.33, -407.578,381.998,- 97.061 m, mn, m, mn, m
For the given data of a close traverse, determine the missing bearings of courses DE and EF then solve the AREA using DMD. Sketch the traverse.
5. A closed traverse with 5 corners has field measured interior angles at each corner as follows, adjust the angles at each corner, equally balanced. A= 101° 28' B= 102° 11’30" C= 104° 42' D=113° 05'30" E= 118° 34' A= B= C= D= E=
27. Given a closed traverse with two interior angles as shown below, and the azimuth of line AB as 350. If the coordinates of point A are XA-1000 and YA= 1000, and the distance AB is 455.80 ft., the X coordinate at B is ft. 105 47 a) 1079.15 b) 920,85 c) 1448.88 d) None of the above
For the given data of a close traverse, determine the missing bearings of courses DE and EF then solve the AREA using DMD. Sketch the traverse. LINE DISTANCE (m) BEARING S АВ 74 N 71°26' E ВС 100 ? 66 S 85°18' E CD DE 128 S 76°21' W EF N 32°16' W FA 51 N 32°35' E
6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and for 15 distances: B umise los A = 38°30' B = 100°38' C = 149°50 Basigns no 11100D = 85°59' AB= 371.006 m BC = 110.222 m CD = 139.872 m DE 103.119 m E = 165°03' EA = 319.860 m +2- 725121 Moto C D unde Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. 201 Az. = 306°31' E FIGURE 6.24 Sketch for Problem 6.16. A