6.1010 kNA6.112m3 kN/m+2m115 KN+3 mFigure 6.3920 KND4 kN/m3 m5 KN77777771 m[R = 44,875 kN, R. 29,125 KN: V28,87 kN, B,M= 49,375 kN.m, D: PCF 1,211 m from F and 2,947 m from A]

Name: 6.1010 kNA6.112m3 kN/m+2m115 KN+3 mFigure 6.3920 KND4 kN/m3 m5 KN7777
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Description: 6.1010 kNA6.112m3 kN/m+2m115 KN+3 mFigure 6.3920 KND4 kN/m3 m5 KN77777771 m[R = 44,875 kN, R. 29,125 KN: V28,87 kN, B,M= 49,375 kN.m, D: PCF 1,211 m from F and 2,947 m from A]

Find the support reactions, maximum shear force and bending moment, location of point of…

Engineering

Mechanical Engineering

6.10 10 KN 6.11 2m 3 kN/m An + 2m 115 KN C + 3 m Figure 6.39 20 kN D 4 kN/m 3 m 5 KN Thin 1 m +1 [R₁ = 44,875 kN, R. = 29,125 KN; V. -28,87 kN, B; M. 49,375 kN.m, D: PCF 1.211 m from F and 2.947 m from A]

6.10 10 KN 6.11 2m 3 kN/m An + 2m 115 KN C + 3 m Figure 6.39 20 kN D 4 kN/m 3 m 5 KN Thin 1 m +1 [R₁ = 44,875 kN, R. = 29,125 KN; V. -28,87 kN, B; M. 49,375 kN.m, D: PCF 1.211 m from F and 2.947 m from A]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Topic Video

Question

6.10
10 kN
A
6.11
2m
3 kN/m
+
2m
115 KN
+
3 m
Figure 6.39
20 KN
D
4 kN/m
3 m
5 KN
7777777
1 m
[R = 44,875 kN, R. 29,125 KN: V28,87 kN, B,
M
= 49,375 kN.m, D: PCF 1,211 m from F and 2,947 m from A]

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Step 1: Given data

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Step 2: Calculation of support reactions

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Step 3: Calculation of shear force diagram

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Step 4: Calculation of shear force diagram

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Step 5: Calculation of bending moment diagram

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Step 6: Calculation of point of contraflexure

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Step 7: Draw shear force and bending moment diagram for given beam

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