6.1 Calculate the ultimate moment M, of the column section shown in Fig. P.6.1 for: (a)N-400 kN. (b) Na-800 kN and (c) Na 1500 kN.Materials are C25 and $420. Use design strengths. (f.-17 MPa and f-365 MPa)Longitudinal reinforcement: 10-16.Dimensions = mm10-016Figure P6.1O Recalculate the moment capacity of the column section shown in Fig. P.6.1 byneglecting the intermediate steel for; (a) N₁-400 kN, (b) N₁-800 kN and (c)N-1500 KN.Materials: C25 and S420.Compare results of Problems 6.1 and 6.2 and discuss.Calculate the ultimate moment M, for the cross-section shown in Fig. P.6.2, for (a)N-300 kN and (b) Nd=1000 kN.Materials: C20 (fcd=13 MPa) and S420 (fyd-365 MPa)Reinforcement: 6-018140500 mm150300 mm35 140

Answered: Image /qna-images/answer/8849e56c-dd91-4a36-987a-589e4eabab6c.jpg

6.1 Calculate the ultimate moment M, of the column section shown in Fig. P.6.1 for: (a) N-400 kN. (b) Na-800 kN and (c) Na 1500 kN. Materials are C25 and $420. Use design strengths. (f.-17 MPa and fy-365 MPa) Longitudinal reinforcement: 10-16. Dimensions = mm 10-016 Figure P6.1 Recalculate the moment capacity of the column section shown in Fig. P.6.1 neglecting the intermediate steel for; (a) N₁-400 kN, (b) N₁-800 kN and N-1500 KN. Materials: C25 and $420. Compare results of Problems 6.1 and 6.2 and discuss. Calculate the ultimate moment M, for the cross-section shown in Fig. P.6.2, fo N-300 kN and (b) Na-1000 kN. $100 (f 265 MB) 140 500 mm 150 300 mm 35 140

6.1 Calculate the ultimate moment M, of the column section shown in Fig. P.6.1 for: (a) N-400 kN. (b) Na-800 kN and (c) Na 1500 kN. Materials are C25 and $420. Use design strengths. (f.-17 MPa and fy-365 MPa) Longitudinal reinforcement: 10-16. Dimensions = mm 10-016 Figure P6.1 Recalculate the moment capacity of the column section shown in Fig. P.6.1 neglecting the intermediate steel for; (a) N₁-400 kN, (b) N₁-800 kN and N-1500 KN. Materials: C25 and $420. Compare results of Problems 6.1 and 6.2 and discuss. Calculate the ultimate moment M, for the cross-section shown in Fig. P.6.2, fo N-300 kN and (b) Na-1000 kN. $100 (f 265 MB) 140 500 mm 150 300 mm 35 140

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1.13 The section shown in Fig. 3.34 represents a beam in a structure containing prefabricated elements. The total width and total depth are limited to 350mm and 530mm respectively. Tension reinforcement used is four $28 bars. Using fe-28 MP and fy=420 MPa, determine the design moment strength of the section. 65 465 100 125 100 350 125 8 = 0.003 N.A. + 0.85fc T=A,fy T z=d-y
Dont round off initial values, round off final ans only pls
AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P = 18 kips, w = 5.6 kips/ft, LAB = 5.0 ft, LBC = 5.0 ft, and LCD = 13.6 ft. Determine the magnitude of the maximum bending stress in the beam. LAB LBC LCD Answer: i ksi Omax
Design the reinforcement of a rectangular beam to resist a dead load moment of 200kN.m (including its own weight) and a live load moment of 300kN.m. The beam is limited in size to 350mm by 600mm overall depth. Steel covering from centroid of bars to outermost fiber is 100mm for both tension and compression reinforcement. Use fc'=27.5Mpa, fy = 414MPa,20mm barsA. As'= 7 of 20mm and As=14 of 20mmB. As' = 9 of 20mm and As=18 of 20mmC. As'= 5 of 20mm and As=10 of 20mmD. As' = 3 of 20mm and As=6 of 20mm Please provide neat and clear solutions Note: kindly check below answer
For the given reinforced T-section shown in Figure 2 with fc’= 30 MPa, fy = 400 MPa, calculate the moment resistance (Mr).
For the Beam section below, check if steel yields and determine the ACI design flexural strength. 12 in. 15 in. 4 #10 bars $3 in. f, = 60,000 psi f;= 4000 psi -18 in.-
Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in
Calculate the design bending strength for the doubly reinforced rectangular section where A’s = 2500 mm2 f’c= 30 MPa & fy = 350 MPa if As =8500 mm2
Hello help me answer this. Thank you.
AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P= 23 kips, w = 4.2 kips/ft, LAB = 3.4 ft, LBC = 3.4 ft, and LcD = 15.6 ft. Determine the magnitude of the maximum bending stress in the beam. B |C LAB LBC LCD Answer: Omax = ksi
Answer in two decimal places please
Find the allowable bending stress for the following shapes. Assume adequate lateral support for the compression flange. a.) W30 x132 of A36 Steel