How to come up to Iz (m,n)= 0.10685 126.0m4(a)Divide the rec tan gle into 4 partsb = ; = 4.5Зт4.5 = 0.75m =Z.6.= = 0.53n =U sin g graph1, (т, п) — 0. 10685so,q = Q (4 × I,) = 325 (4 × 0. 10685)138. 905 kPa

Given data: B=6m L=9m Im,n=0.10685

6.0m- L = ² = 3m b = 4,5 1 m = 3 (a) Divide the rec tan gle into 4 parts b = ² = 4.5 = 0.75 n = //=/²/2 = 0.5 9.0m 2 4 Z U sing graph I₂ (m, n) = 0.10685 SO, q= Q(4x1₂) = 325 (4 x 0. 10685) = 138.905 kPa

6.0m- L = ² = 3m b = 4,5 1 m = 3 (a) Divide the rec tan gle into 4 parts b = ² = 4.5 = 0.75 n = //=/²/2 = 0.5 9.0m 2 4 Z U sing graph I₂ (m, n) = 0.10685 SO, q= Q(4x1₂) = 325 (4 x 0. 10685) = 138.905 kPa

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

How to come up to Iz (m,n)= 0.10685

1
2
6.0m
4
(a)
Divide the rec tan gle into 4 parts
b = ; = 4.5
Зт
4.5 = 0.75
m =
Z.
6.
= = 0.5
3
n =
U sin g graph
1, (т, п) — 0. 10685
so,
q = Q (4 × I,) = 325 (4 × 0. 10685)
138. 905 kPa

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