6.0m- L = ² = 3m b = 4,5 1 m = 3 (a) Divide the rec tan gle into 4 parts b = ² = 4.5 = 0.75 n = //=/²/2 = 0.5 9.0m 2 4 Z U sing graph I₂ (m, n) = 0.10685 SO, q= Q(4x1₂) = 325 (4 x 0. 10685) = 138.905 kPa

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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How to come up to Iz (m,n)= 0.10685

1
2
6.0m
4
(a)
Divide the rec tan gle into 4 parts
b = ; = 4.5
Зт
4.5 = 0.75
m =
Z.
6.
= = 0.5
3
n =
U sin g graph
1, (т, п) — 0. 10685
so,
q = Q (4 × I,) = 325 (4 × 0. 10685)
138. 905 kPa
Transcribed Image Text:1 2 6.0m 4 (a) Divide the rec tan gle into 4 parts b = ; = 4.5 Зт 4.5 = 0.75 m = Z. 6. = = 0.5 3 n = U sin g graph 1, (т, п) — 0. 10685 so, q = Q (4 × I,) = 325 (4 × 0. 10685) 138. 905 kPa
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