6. You want to find the dimensions of the rectangle with the largest area that can be inscribed in the equation parabola y = 4 - x and the x-axis as shown in the following graphic: If x and y represent the dimensions of the inscribed rectangle shown, then when using the method of the Lagrange multipliers, the Lagrangian L corresponds to A) L(r, y, A) = ry – A(x² + 4y – 16). B) L(r, y, A) = ry - Mx² + 2y – 8). C) L(r, y, A) = 2.ry – X(r² + y – 4). D) L(r, y, A) = ry – X(2x? + 2y – 8).
6. You want to find the dimensions of the rectangle with the largest area that can be inscribed in the equation parabola y = 4 - x and the x-axis as shown in the following graphic: If x and y represent the dimensions of the inscribed rectangle shown, then when using the method of the Lagrange multipliers, the Lagrangian L corresponds to A) L(r, y, A) = ry – A(x² + 4y – 16). B) L(r, y, A) = ry - Mx² + 2y – 8). C) L(r, y, A) = 2.ry – X(r² + y – 4). D) L(r, y, A) = ry – X(2x? + 2y – 8).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:6. You want to find the dimensions of the rectangle
with the largest area that can be inscribed in the
equation parabola y = 4 - x' and the x-axis
as shown in the following graphic:
If x and y represent the dimensions of the inscribed rectangle shown, then when using the method of
the Lagrange multipliers, the Lagrangian L corresponds to
A) L(r, y, A) = ry – A(x² + 4y – 16).
B) L(r, y, A) = ry - Mx² + 2y – 8).
C) L(r, y, A) = 2ry – (r² + y – 4).
D) L(1,y, A) = ry – (2x² + 2y – 8).
%3D
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