6. You have a jar full of M&Ms. 8 are Black, 5 are Green, and 3 are Yellow. Let B means you drew a Black, G means you drew a Green and Y means you drew a Yellow. A. Assume you draw one M&M at random for each trial and replace it before the next trial. I. II. III. Is the first draw Independent from the 2nd draw? Does P(1st Draw is G | 1st Draw isn't B) = P(1st Draw is G)? Does P(1st Draw is G | 2nd Draw isn't B) = P(1st Draw is G)?
6. You have a jar full of M&Ms. 8 are Black, 5 are Green, and 3 are Yellow. Let B means you drew a Black, G means you drew a Green and Y means you drew a Yellow. A. Assume you draw one M&M at random for each trial and replace it before the next trial. I. II. III. Is the first draw Independent from the 2nd draw? Does P(1st Draw is G | 1st Draw isn't B) = P(1st Draw is G)? Does P(1st Draw is G | 2nd Draw isn't B) = P(1st Draw is G)?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![### Problem 6: Probability with M&Ms
You have a jar full of M&Ms. The distribution is as follows: 8 are Black, 5 are Green, and 3 are Yellow. Let:
- **B** represent drawing a Black M&M.
- **G** represent drawing a Green M&M.
- **Y** represent drawing a Yellow M&M.
#### Part A: Drawing with Replacement
Assume you draw one M&M at random for each trial and replace it before the next trial.
1. **Is the first draw independent from the second draw?**
2. **Does the probability that the first draw is Green given that the first draw isn't Black equal the probability that the first draw is Green?**
\[
P(\text{1st Draw is G } | \text{ 1st Draw isn't B}) = P(\text{1st Draw is G})
\]
3. **Does the probability that the first draw is Green given that the second draw isn't Black equal the probability that the first draw is Green?**
\[
P(\text{1st Draw is G } | \text{ 2nd Draw isn't B}) = P(\text{1st Draw is G})
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e1ac192-34c8-4938-afeb-f8369c94da2d%2F08b95b10-1d54-4189-aa3a-c27c1b5f2f86%2Fbcykbeo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem 6: Probability with M&Ms
You have a jar full of M&Ms. The distribution is as follows: 8 are Black, 5 are Green, and 3 are Yellow. Let:
- **B** represent drawing a Black M&M.
- **G** represent drawing a Green M&M.
- **Y** represent drawing a Yellow M&M.
#### Part A: Drawing with Replacement
Assume you draw one M&M at random for each trial and replace it before the next trial.
1. **Is the first draw independent from the second draw?**
2. **Does the probability that the first draw is Green given that the first draw isn't Black equal the probability that the first draw is Green?**
\[
P(\text{1st Draw is G } | \text{ 1st Draw isn't B}) = P(\text{1st Draw is G})
\]
3. **Does the probability that the first draw is Green given that the second draw isn't Black equal the probability that the first draw is Green?**
\[
P(\text{1st Draw is G } | \text{ 2nd Draw isn't B}) = P(\text{1st Draw is G})
\]
Expert Solution
Step 1
Given:
Number of black balls=8
Number of green balls=5
Number of yellow balls=3
Step by step
Solved in 2 steps
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