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6. y = x2 (-2,4) УА О (1,6) (2,4) 3y=2x + 16 y=-2x+8 X

6. y = x2 (-2,4) УА О (1,6) (2,4) 3y=2x + 16 y=-2x+8 X

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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6. y = x2 (-2, 4) УА 0 (1,6) (2,4) 3y=2x+16 y=-2x+8 S X
Transcribed Image Text:6. y = x2 (-2, 4) УА 0 (1,6) (2,4) 3y=2x+16 y=-2x+8 S X
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