**Question 6: Conversion from Machine Language to Assembly Language for MARIE****Objective:** Translate the given MARIE machine language instructions into their assembly language equivalents.**Instructions:**a) **Machine Language:** 0000010111000000 - **Assembly Language:** ADD Xb) **Machine Language:** 0001101110010010 - **Assembly Language:** SUB Yc) **Machine Language:** 1100100101101011 - **Assembly Language:** JUMP Z**Explanation:**- MARIE (Machine Architecture that is Really Intuitive and Easy) is a simple educational model of a computer that helps students and learners understand basic computer architecture and assembly language.- Each machine language instruction consists of a 16-bit binary code, with the first four bits typically representing the opcode and the remaining bits representing the address or data.- The conversion requires familiarity with MARIE’s instruction set, where particular opcodes correspond to specific operations (e.g., ADD, SUB, JUMP), followed by an address or a data label reference.This exercise helps in understanding how high-level assembly translations correspond directly to binary operations executed by the machine. Learners are encouraged to practice translating more instructions to enhance their understanding of computer instruction sets.

Name: **Question 6: Conversion from Machine Language to Assembly Language f
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: **Question 6: Conversion from Machine Language to Assembly Language for MARIE****Objective:** Translate the given MARIE machine language instructions into their assembly language equivalents.**Instructions:**a) **Machine Language:** 000001011100000

ANSWER:-MARIE machine Language The Instruction SM Architecture (ISA) of a machine specifies the instructions that the computer can perform and the format of each instruction. The ISA is essentially an interface between the software and the hardware Each instruction of MARIE consists of 16 Bits. The most significant (12-15) specify the opcode The opcode specifies the instruction to be executed. The least significant bits (0-11) from the address MARIE's Instruction format OPCODE ADDRESS Thus, the first four (most significant) bits i.e 15-12 contain the opcode while the remaining contain the address a) consider the -following MARIE machine language instruction: OPCODE ADDRESS 0000 0101 1100 0000 We look up the value of the opcode in the Instruction Set Architecture (ISA). We also co vest the binary address into its hexadecimal equivalent. Thus, the resulting assembly instruction is: jn S 5C0. b) Consider the following MARIE machine language instruction: OPCODE ADDRESS 0001 1011 1001 0010 We Wok up the value of the op.de in the Intruction Set Architecture (ISA). We also co vert the binary address into its hexadecimal equivalent. Thus, resulting assembly instruction is: Load B92. c) consider the following MARIE machine language instruction: OPCODE ADDRESS 1100 1001 0110 1011 We look up the value of the opcode In the lntruction Set Architecture (ISA). We also convert the binary address into its hexadecimal equivalent. Thus, the resulting assembly instruction is: Jumpl 96B.