Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
6. What mass of KBr is present in 25 mL of a 0.85 M solution of
potassium chloride?

Transcribed Image Text:As a rough estimate, 85 g divided by 75 g/mol is about 1 mol. If you
divide 1 mol by 0.4 L you get 2.5 M. This approximation agrees with
0.4000 L
ol/L = 2.85 M KCI
O Verify your results.
the answer of 2.85 M.
PRACTICE
1 Vinegar contains 5.0 g of acetic acid, CH3COOH, in 100.0 mL of solution.
Calculate the molarity of acetic acid in vinegar.
If 18.25 g HCl is dissolved in enough water to make 500.0 mL of
solution, what is the molarity of the HCl solution?
3 If 20.0 g H2SO4 is dissolved in enough water to make 250.0 mL
of solution, what is the molarity of the sulfuric acid solution?
A solution of AgNO3 contains 29.66 g of solute in 100.0 mL of solution.
What is the molarity of the solution?
A solution of barium hydroxide, Ba(OH)2, contains 4.285 g of barium
hydroxide in 100.0 mL of solution. What is the molarity of the solution?
What mass of KBr is present in 25 mL of a 0.85 M solution of
potassium chloride?
If all the water in 430.0 mL of a 0.45 M NaCl solution evaporates, what
mass of NaCl will remain?
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