**Question 6: What is the correct IUPAC name of the following compound?**The compound is represented by a structural formula. It consists of a four-carbon butane backbone with the following groups attached:- A methyl group (CH₃) at the first carbon.- A hydroxyl group (OH) at the third carbon.- A bromine atom (Br) at the second carbon.The possible IUPAC names with stereochemistry are listed as follows:A) (2S, 3S)-3-bromo-2-butanol B) (2R, 3S)-2-bromo-3-butanol C) (2R, 3S)-3-bromo-2-butanol D) (2R, 3R)-2-bromo-3-butanol E) (2R, 3R)-3-bromo-2-butanol F) (2S, 3R)-2-bromo-3-butanol G) (2S, 3R)-3-bromo-2-butanol H) (2S, 3S)-2-bromo-3-butanol **Explanation of Structural Formula:**- Vertical Line: Represents the carbon backbone of butane.- Horizontal Groups: Indicate the positions of OH and Br groups with respect to the main carbon chain.To correctly name the compound, the stereochemistry (R/S configuration) needs to be determined based on the 3D arrangement of the groups around the chiral centers.

The principal functional group is OH. So, naming will be ended with 'ol'. The longest carbon chain contains 4 carbons. Hence, but term will come. One bromo is present as substituent at C-3 position. R/S nomenclature is based on CIP rule which states that higher is the atomic number of directly attached to higher will be the priority. On these basis IUPAC name is : (G). (2S, 3R) 3-bromo-2-butanol. Details are shown in image.