6. Using the Newton's backward interpolation formula construct an interpolation polynomial of degree 3 for the data f(- 0.75) = - 0.07181250, f(- 0.5) = - 0.024750, f(- 0.25) = 0.33493750, f(0) = 1.1010. Hence, find f(- 1/3).
6. Using the Newton's backward interpolation formula construct an interpolation polynomial of degree 3 for the data f(- 0.75) = - 0.07181250, f(- 0.5) = - 0.024750, f(- 0.25) = 0.33493750, f(0) = 1.1010. Hence, find f(- 1/3).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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![6. Using the Newton's backward interpolation formula construct an interpolation polynomial of degree 3
for the data f(- 0.75) = - 0.07181250, 1(- 0.5) = - 0.024750, f(- 0.25) = 0.33493750, 1(0) = 1.1010.
Hence, find f(- 1/3),](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ee8ba0b-5200-4c03-bbd7-865efd3346fa%2F55651e4e-2923-4ed8-9462-41e39d16e4a7%2Fab0trqq_processed.png&w=3840&q=75)
Transcribed Image Text:6. Using the Newton's backward interpolation formula construct an interpolation polynomial of degree 3
for the data f(- 0.75) = - 0.07181250, 1(- 0.5) = - 0.024750, f(- 0.25) = 0.33493750, 1(0) = 1.1010.
Hence, find f(- 1/3),
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