6. Using the method of variation of parameters, what is the form of a particular solution of (D³ -4D)y=x-3e²x₂ A. 3p = Ax+ Be 2x + Ce-2x C. 3p = Ax+B cos 2x + C sin 2x B. p = Ax² + Bx³ + Cxe 2x D. 3p=A+Be2x + Ce-2x
6. Using the method of variation of parameters, what is the form of a particular solution of (D³ -4D)y=x-3e²x₂ A. 3p = Ax+ Be 2x + Ce-2x C. 3p = Ax+B cos 2x + C sin 2x B. p = Ax² + Bx³ + Cxe 2x D. 3p=A+Be2x + Ce-2x
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![6. Using the method of variation of parameters, what is the form of a particular solution of
(D³ -4D)y=x-3e²x2
A. 3p = Ax + Be 2x + Ce-2x
C. 3p = Ax+B cos 2x + C sin 2x
A
A
B) B
© C
с
D) D
p = Ax² + Bx ³ +Cxe 2x
В. Ур
D. 3p = A + Be²x +
+ Ce-2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F022c69db-e653-439e-8eaa-456373c640d0%2F424d5703-ca41-4868-9c9b-b7ae9967049f%2Fytzhjie_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Using the method of variation of parameters, what is the form of a particular solution of
(D³ -4D)y=x-3e²x2
A. 3p = Ax + Be 2x + Ce-2x
C. 3p = Ax+B cos 2x + C sin 2x
A
A
B) B
© C
с
D) D
p = Ax² + Bx ³ +Cxe 2x
В. Ур
D. 3p = A + Be²x +
+ Ce-2x
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