**Stock Trade Volume Analysis**This educational exercise involves analyzing the trade volume of a stock, measured as the number of shares traded on a given day. The data is presented in two samples, each representing 40 trading days in a year.**Objective:**1. **Point Estimate:** - Use the first sample to compute a point estimate for the average number of shares traded per day over the year. - Fill in the blank: A point estimate for the population mean number of shares traded per day in the year is _______ million. (Express to three decimal places.)2. **Confidence Interval (Sample 1):** - Construct a 95% confidence interval for the population mean number of shares traded per day using the first sample. - Choose the correct interpretation: - A. One can be _______% confident... - B. The number of shares traded per day is between ______ million and ______ million... - C. One can be _______% confident... - D. There is a _______% probability...3. **Confidence Interval (Sample 2):** - Using the second sample, construct another 95% confidence interval. - Choose how to interpret this interval: - A. One can be ______ % confident... - B. The number of shares traded per day is between ______ million and ______ million... - C. There is a ______ % probability... - D. One can be ______ % confident...4. **Compare Intervals:** - Explain why the confidence intervals from parts (b) and (c) differ. - Choose from: - A. Different sample sizes affect the interval. - B. Possible error in one of the samples. - C. Different populations represented. - D. Variation in sampling affects results.**Data Tables:**- **First Sample Volumes (millions of shares traded):** - 6.22, 4.04, 6.22, 5.76, 3.84, 2.94, 4.62, 2.92, etc.- **Second Sample Volumes (millions of shares traded):** - 8.74, 8.66, 7.60, 4.64, 4.82, 4.52, 3.30, 5.46, etc.These samples provide the necessary data for students ### Understanding the t-Distribution Table#### OverviewThe table presented displays critical values of the t-distribution for various degrees of freedom and significance levels. The t-distribution is crucial in statistics, especially for small sample sizes or when the population standard deviation is unknown.#### Graph ExplanationAt the top left of the image is a simple bell curve graph representing a t-distribution. The shaded area on the right tail of the curve emphasizes the area in the right tail for which the critical values are provided in the table.#### Table Structure- **Degrees of Freedom (df):** This is the first column in the table, ranging from 1 to 100, followed by selected values up to 1000. Degrees of freedom are crucial in determining the shape of the t-distribution curve.- **Area in Right Tail:** The headers of the remaining columns represent the cumulative probability (α-level) for which the critical value is calculated. These are the areas under the curve's right tail: 0.25, 0.20, 0.15, 0.10, 0.05, 0.025, 0.02, 0.01, 0.005, 0.0025, 0.001, 0.0005.#### How to Use the TableTo find a critical value:1. Identify the degrees of freedom for your dataset.2. Choose the desired significance level (e.g., 0.05) corresponding to your hypothesis test.3. Locate the intersection of the degrees of freedom row and the significance level column.#### Sample EntriesFor example, with 10 degrees of freedom and a significance level of 0.05, the critical t-value is 1.812.- **Degrees of Freedom: 1** - 0.25 → 1.000 - 0.05 → 6.314 - 0.005 → 63.657- **Degrees of Freedom: 10** - 0.25 → 0.700 - 0.05 → 1.812 - 0.005 → 4.587This table is an essential tool for students and educators working with statistical analyses involving the t-distribution.

Since you have posted a question with multiple subparts, we will solve first three subparts for you. To get remaining subparts solved, please repost the question and mention the subparts to be solved. Confidence interval is calculated by interval range within which the true value of the parameter exist. It is calculated by the combined value of the sample statistic and the margin of error. It is defined as : x¯±t0.05×snGiven : The trade volume of the stock of first accompanying table and the second accompanying table was, First sample : 6.22,4.04,6.22,5.76,3.84,2.94,4.62,2.92,3.24,8.90,4.60,2.84,6.52,5.76,3.32,4.58,3.16,3.82,3.34,5.38,2.94,2.22,6.12,6.02,5.66,3.48,3.00,9.36,5.68,3.88,4.04,3.48,3.74,3.70,4.06,5.20,3.62,3.60,3.28,1.60 a) Point estimate of population mean number of share : x¯1=∑x1n=6.22+4.04+6.22+...+1.6040=176.740=4.4175 The point estimate for the mean number of shares traded per year is 4.418 million.b) standard deviation : s1=∑x-x¯2n-1=6.22-4.1482+4.04-4.1782+...+1.60-4.178240-1=2.6979=1.643 The critical value at 0.05 for 39 degree of freedom is 2.023 (Two tailed) Confidence interval at 95% : CI=x¯±t0.05×sn=4.418±2.023×1.64340=4.418±0.526=4.418-0.526,4.418+0.526=3.892,4.944 Hence option B is correct The number of shares of the stocks traded per day is between 3.892 and 4.944 Incorrect options : Option A - Confidence interval explains the true value of the parameter interval Option C - It explains the ranges of interval where the true value of the parameter Option D - A day mean value is not explain by the confidence intervalc) Second sample : 8.74,8.66,7.60,4.64,4.84,4.52,3.30,5.46,10.38,4.76,6.64,4.88,4.48,5.48,2.74,3.20,3.42,3.28,4.40,2.86,2.96,4.10,7.50,6.60,5.36,4.88,3.34,2.76,6.24,3.38,3.58,4.10,7.18,3.42,4.40,3.08,1.68,4.38,3.38,3.54 Mean : x¯2=∑x2n=8.74+8.66+7.60+...+3.5440=190.1440=4.7535 Standard deviation : s2=∑x-x¯2n-1=8.74-4.75352+8.66-4.75352+...+3.54-4.7535240-1=3.6484=1.910 The critical value at 0.05 for 39 degree of freedom is 2.023 (Two tailed) Confidence interval at 95% : CI=x¯±t0.05×sn=4.735±2.023×1.91040=4.735±0.611=4.735-0.611,4.735+0.611=4.124,5.346 Hence option B is correct The number of shares of the stocks traded per day is between 4.124 and 5.346 Incorrect options : Option A - Confidence interval explains the true value of the parameter interval Option C - It explains the ranges of interval where the true value of the parameter Option D - A day mean value is not explain by the confidence interval

Math

Statistics

6. The trade volume of a stock is the number of shares traded on a given day. The data in the first accompanying table, in millions (so that 6.22 represents 6,220,000 shares traded), represent the volume of a certain stock traded for a random sample of 40 trading days in a certain year. A second random sample of 40 days in the same year resulted in the data in second accompanying table. Complete parts (a) through (d) below. Click here to view the data for the first sample. Click here to view the data for the second sample.11 Click here to view the table of critical t-values. 12 10 (a) Use the data from the first sample to compute a point estimate for the population mean number of shares traded per day in the year. A point estimate for the population mean number of shares traded per day in the year is (Round to three decimal places as needed.) million. (b) Using the data from the first sample, construct a 95% confidence interval for the population mean number of shares traded per day in the certain year. Interpret the confidence interval. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to three decimal places as needed.) A. One can be % confident that the mean number of shares of the stock traded in all days of the specifie B. The number of shares of the stock traded per day is between million and million for C. One can be % confident that the mean number of shares of the stock traded per day in the specified D. There is a % probability that the mean number of shares of stock traded per day in the specified year (c) Using the data from the second sample, construct another 95% confidence interval for the population mean number of shares traded per day in the year. Interpret the confidence interval. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to three decimal places as needed.) A. One can be % confident that the mean number of shares of the stock traded per day in the specified B. The number of shares of the stock traded per day is between million and million for C. There is a % probability that the mean number of shares of stock traded per day in the specified year D. One can be % confident that the mean number of shares of the stock traded in all days of the specifie