6. The sick-leave time of employees in a firm in a month is normally distributed with amean of 100 hours and a standard deviation of 20 hours. Find the probability thatthe sick-leave time of an employee in a month exceeds 130 hours. •Types of functions to expressprobability distribution(a) Probability Mass Function (PMF)f(x) = P(x = x)(b) Cumulative Distribution Functions (CDF)f(x) = P(X ≤ x)MeanM = { xf(x)Variance0² = [x²f (x) - μ²Standard Deviation.0x TotDiscrete Uniform Distributionf(x) = //12M =0² =b+ a2(b-a+1)²12•Binomial Distribution(f(x) = (~) p² (1-P)^-xс прnp(1-P)1• Hypergeometric Distribution(*) (*)(~)f(x) =и = пр8² = np(1-P/(N=1)whereK/NP=·Poisson Distribution-^+ (^T)*X!f(x) = eM = AT0² = NTWhereN = population sizesample size /no. of trialsPprobability-p = probability of success on asingle trialK = no. of successes in the populationin the sampleofX - no.successes

mean = 100 hour standard deviation = 20 hours X = Sick leave time in hour

Answered: 6. The sick-leave time of employees in…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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6. The sick-leave time of employees in a firm in a month is normally distributed with a mean of 100 hours and a standard deviation of 20 hours. Find the probability that the sick-leave time of an employee in a month exceeds 130 hours.