6. The median to the base of an isosceles triangle is the perpendicular bisector of the base. RESTATEMENT Given: Isosceles triangle ABC with AC BC and median CD Prove: CD is the perpendicular bisector of AB. B D
6. The median to the base of an isosceles triangle is the perpendicular bisector of the base. RESTATEMENT Given: Isosceles triangle ABC with AC BC and median CD Prove: CD is the perpendicular bisector of AB. B D
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
Isosceles Triangle (Theorem)
![6. The median to the base of an isosceles triangle is the
perpendicular bisector of the base.
RESTATEMENT
Given: Isosceles triangle ABC with
AC BC and median CD
Prove: CD is the perpendicular
bisector of AB.
A
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5937b57-a9c8-4d27-92ab-4801589ffd51%2F106ebe6e-b1cc-43da-a894-862bfebc1b77%2Fue85b2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. The median to the base of an isosceles triangle is the
perpendicular bisector of the base.
RESTATEMENT
Given: Isosceles triangle ABC with
AC BC and median CD
Prove: CD is the perpendicular
bisector of AB.
A
D
![Puoor
Statement
Reasuns
1. AC BC
Median CD of AABC
1.
2. Dis the midpoint of
AB.
2.
3. Definition of midpoint
4.
3.
4. ZA ZB
6. ACAD ACBD
6. ZCDA s 2CDB
7, 2CDA andZCDB
form a linear pair.
5.
7.
8. Linear Pair Postulate
9. Theorem 61
10. Definition of perpen-
dieular segments
8.
9.
10. CD is perpendicular
to AB.
11.
అ
11.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5937b57-a9c8-4d27-92ab-4801589ffd51%2F106ebe6e-b1cc-43da-a894-862bfebc1b77%2Fm13s69r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Puoor
Statement
Reasuns
1. AC BC
Median CD of AABC
1.
2. Dis the midpoint of
AB.
2.
3. Definition of midpoint
4.
3.
4. ZA ZB
6. ACAD ACBD
6. ZCDA s 2CDB
7, 2CDA andZCDB
form a linear pair.
5.
7.
8. Linear Pair Postulate
9. Theorem 61
10. Definition of perpen-
dieular segments
8.
9.
10. CD is perpendicular
to AB.
11.
అ
11.
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